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Let the number be 'n' & 'n+1' ; consecutive.
Hence
n(n+1) = 7310 ( product)
n^(2) + n = 7310
Complete the Square
( n + 1/2)^(2) - (1/2)^(2) = 7310
( n + 1/2)^2 - 1/4 = 7310
(n + 1/2)^(2) = 7310.25
Square root both sides
n+ 1/2 = +/- 85.5 (NB 1/2 = 0.5)
n = 85.5 - 0.5 = 85
Hence n + 1 = 86
Verification 85 X 86 = 7310
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They are: 85 times 86 = 7310
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Find two consecutive numbers with the value of 4160
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What are two consecutive numbers with the product of 7310?
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Find two consecutive numbers with a product of 4160?
Find two consecutive numbers with the value of 4160
What one-digit number is the product of two consecutive prime numbers?
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