They are: 85*86 = 7310
Two consecutive two digit numbers that when multiplied give the product of 812 are 28 and 29.
two consecutive numbers with the product of 1722 = 41 & 42
23x24.
The numbers are 56 and 57.
The numbers are 28 and 29.
They are: 85 times 86 = 7310
Let the number be 'n' & 'n+1' ; consecutive. Hence n(n+1) = 7310 ( product) n^(2) + n = 7310 Complete the Square ( n + 1/2)^(2) - (1/2)^(2) = 7310 ( n + 1/2)^2 - 1/4 = 7310 (n + 1/2)^(2) = 7310.25 Square root both sides n+ 1/2 = +/- 85.5 (NB 1/2 = 0.5) n = 85.5 - 0.5 = 85 Hence n + 1 = 86 Verification 85 X 86 = 7310
Find two consecutive numbers with the value of 4160
Two consecutive two digit numbers that when multiplied give the product of 812 are 28 and 29.
There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)
two consecutive numbers with the product of 1722 = 41 & 42
23x24.
Yes.
They are 14 and 15.
The numbers are 14 and 15.
The numbers are 103 and 104.
The numbers are 23 and 24.