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They are: 85*86 = 7310

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Q: Which two consecutive numbers have a product of 7310?
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Related questions

What are two consecutive numbers with the product of 7310?

They are: 85 times 86 = 7310


What are the two consecutive numbers with a product of 7310?

Let the number be 'n' & 'n+1' ; consecutive. Hence n(n+1) = 7310 ( product) n^(2) + n = 7310 Complete the Square ( n + 1/2)^(2) - (1/2)^(2) = 7310 ( n + 1/2)^2 - 1/4 = 7310 (n + 1/2)^(2) = 7310.25 Square root both sides n+ 1/2 = +/- 85.5 (NB 1/2 = 0.5) n = 85.5 - 0.5 = 85 Hence n + 1 = 86 Verification 85 X 86 = 7310


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There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)


What two consecutive two digit numbers multiplied give the product of 812?

Two consecutive two digit numbers that when multiplied give the product of 812 are 28 and 29.


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