Two consecutive two digit numbers that when multiplied give the product of 812 are 28 and 29.
two consecutive numbers with the product of 1722 = 41 & 42
The numbers are 56 and 57.
The numbers are 42 and 43.
23x24.
They are: 85 times 86 = 7310
Let the number be 'n' & 'n+1' ; consecutive. Hence n(n+1) = 7310 ( product) n^(2) + n = 7310 Complete the Square ( n + 1/2)^(2) - (1/2)^(2) = 7310 ( n + 1/2)^2 - 1/4 = 7310 (n + 1/2)^(2) = 7310.25 Square root both sides n+ 1/2 = +/- 85.5 (NB 1/2 = 0.5) n = 85.5 - 0.5 = 85 Hence n + 1 = 86 Verification 85 X 86 = 7310
Find two consecutive numbers with the value of 4160
There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)
Two consecutive two digit numbers that when multiplied give the product of 812 are 28 and 29.
two consecutive numbers with the product of 1722 = 41 & 42
The numbers are 28 and 29.
The numbers are 56 and 57.
The numbers are 24 and 25.
The numbers are 43 and 44.
They are 14 and 15.
The numbers are 42 and 43.