y = X^2 - 5X + 3 ( set = to 0 )
X^2 - 5X + 3 = 0
Use the quadratic formula. X = -b +/- sqrt(b^2-4ac)/2a
a = 1
b = -5
c = 3
X = -(-5) +/- sqrt[(-5)^2 - 4(1)(3)]/2(1)
X = 5 +/- sqrt(13)/2
X= 4.302775638
X = 0.6972243623
ugly but true. my TI-84 confirms this answer. Probably use the exact answer.
(-3, -5)
A quadratic equation (t=s2+3). This kind of line will result in a parabola like curve.
Left
-12 +/- sq root 104
It is an up parabola.
It is the equation of a parabola.
x = ±2
(-3, -5)
7
The minimum value of the parabola is at the point (-1/3, -4/3)
By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero
(6, 40) and (-1, 5)
type you answer here!
A quadratic equation (t=s2+3). This kind of line will result in a parabola like curve.
The solution comprises every point on a parabola which is symmetric about the y axis and has its apex at (0,1).
Left
x^2+8x=20 x^2+8x-20=0 (x+10)(x-2)=0 x=-10 and x=2 are the roots (intercepts) (-10,0) and (2,0) are the x-intercepts.