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The expression (64 - x^2) can be factored using two distinct methods. First, it can be recognized as a difference of squares, which factors into ((8 - x)(8 + x)). Alternatively, it can be expressed by rewriting it as (- (x^2 - 64)), and then factoring as (- (x - 8)(x + 8)). Both methods yield the same factors but highlight different aspects of the expression.
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How many distinct factors does the number 64 have?
Seven distinct factors.
How many distinct factors does 64 have?
7 factors. They are: 1, 2, 4, 8, 16, 32, 64
How many distinct prime factors does 64 have?
Just the one: 2
Do all even numbers have at least two prime factors?
Not two DISTINCT prime factors, no. For example, 64 = 2^6 only has prime factor 2. All even numbers which are not a power of 2 must have at least two distinct prime factors, however; one of them will, of course, be 2.
What is two thirds of ninety six?
64.
How do you solve x2-64 by factoring?
x2-64 = (x-8)(x+8)
What is the gcf of 64 and 320?
Factoring the two numbers: 64 = 2^6 32 = 2^6 x 5 Thus, 2^6 is the Greatest Common Factor. So, 64 is the GCF of 64 and 320.
How many distinct factors does the number 64 have?
Seven distinct factors.
What are the the distinct factors of 64?
1, 2, 4, 8, 16, 32, 64.
How do you find the asympototes of the hyperbola 16y2 - 4x2-64 equals 0?
Y =sqrt(4x^2 +64/16) I would, after factoring, say +/- 2; horizontally
How many distinct factors does 64 have?
7 factors. They are: 1, 2, 4, 8, 16, 32, 64
How many distinct prime factors does 64 have?
Just the one: 2
What are the distinct factor pair for 64?
(64,1)(32,2)(16,4)(8,8)
What are the distinct factor pairs of 64?
(64,1)(32,2)(16,4)(8,8)
Do all even numbers have at least two prime factors?
Not two DISTINCT prime factors, no. For example, 64 = 2^6 only has prime factor 2. All even numbers which are not a power of 2 must have at least two distinct prime factors, however; one of them will, of course, be 2.
What two-digit numbers have the most factors in their prime factorization?
If you're asking about distinct prime factors, there are eight numbers tied with three of them. If not, 64 has six twos.
What are the distinct factors of 128?
1 2 4 8 16 32 64 128.
