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Seven distinct factors.
7 factors. They are: 1, 2, 4, 8, 16, 32, 64
Just the one: 2
Not two DISTINCT prime factors, no. For example, 64 = 2^6 only has prime factor 2. All even numbers which are not a power of 2 must have at least two distinct prime factors, however; one of them will, of course, be 2.
64.
Factoring the two numbers: 64 = 2^6 32 = 2^6 x 5 Thus, 2^6 is the Greatest Common Factor. So, 64 is the GCF of 64 and 320.
x2-64 = (x-8)(x+8)
Seven distinct factors.
1, 2, 4, 8, 16, 32, 64.
Y =sqrt(4x^2 +64/16) I would, after factoring, say +/- 2; horizontally
7 factors. They are: 1, 2, 4, 8, 16, 32, 64
(64,1)(32,2)(16,4)(8,8)
(64,1)(32,2)(16,4)(8,8)
Just the one: 2
Not two DISTINCT prime factors, no. For example, 64 = 2^6 only has prime factor 2. All even numbers which are not a power of 2 must have at least two distinct prime factors, however; one of them will, of course, be 2.
If you're asking about distinct prime factors, there are eight numbers tied with three of them. If not, 64 has six twos.
1 2 4 8 16 32 64 128.