to factor (x2-16x+64), you need to find two number whose product is 64 and whose sum is 16. These two numbers are 8 and 8. (x2-16x+64)=(x-8)(x-8)
The question does not make sense because it has what appears to be an equation but which contains two "equals"!The question does not make sense because it has what appears to be an equation but which contains two "equals"!The question does not make sense because it has what appears to be an equation but which contains two "equals"!The question does not make sense because it has what appears to be an equation but which contains two "equals"!
It is: 4s = 64
Let x and y be the two numbers. We can set up a system of equations: x + y = 20 and xy = 64. By solving the first equation for y (y = 20 - x) and substituting into the second equation, we get x(20 - x) = 64. Simplifying this quadratic equation gives us x^2 - 20x + 64 = 0. Factoring this equation gives us (x - 16)(x - 4) = 0. Therefore, the two numbers are 16 and 4.
Let the page numbers be x and x+1. The product of two consecutive numbers is x(x+1). Given that the product is 4160, we have the equation x(x+1) = 4160. By solving this quadratic equation, we find that the page numbers are 64 and 65.
to factor (x2-16x+64), you need to find two number whose product is 64 and whose sum is 16. These two numbers are 8 and 8. (x2-16x+64)=(x-8)(x-8)
"Solution" means the number that 'x' must be, in order to make the statement true.The solution to the equation " x = 64 " is . . . . . x = 64
(2)6 = 64
Oh, dude, we got some math riddles here! So, let's break it down - the ratio of 9 to 7 means we're dealing with two numbers that have that kinda relationship. If their sum is 1024, you just gotta do a little math dance to figure out those integers. So, 9x + 7x = 1024, solve for x, and you'll have your numbers. Math, man, it's like solving puzzles but with numbers.
The question does not make sense because it has what appears to be an equation but which contains two "equals"!The question does not make sense because it has what appears to be an equation but which contains two "equals"!The question does not make sense because it has what appears to be an equation but which contains two "equals"!The question does not make sense because it has what appears to be an equation but which contains two "equals"!
It is: 4s = 64
64 times 3.125 = 200
484
Let x and y be the two numbers. We can set up a system of equations: x + y = 20 and xy = 64. By solving the first equation for y (y = 20 - x) and substituting into the second equation, we get x(20 - x) = 64. Simplifying this quadratic equation gives us x^2 - 20x + 64 = 0. Factoring this equation gives us (x - 16)(x - 4) = 0. Therefore, the two numbers are 16 and 4.
Let the page numbers be x and x+1. The product of two consecutive numbers is x(x+1). Given that the product is 4160, we have the equation x(x+1) = 4160. By solving this quadratic equation, we find that the page numbers are 64 and 65.
1 x 64, 2 x 32, 4 x 16, 8 x 8 = 64
Because two negative numbers when multiplied together make a positive number. Second, two positive numbers multiplied together make a positive number. Here is an example: What is the square root of 64? 8 X 8 = 64 -8 X -8 = 64 So the two square roots of 64 are 8 and -8.