8*8
and
8 squared
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to factor (x2-16x+64), you need to find two number whose product is 64 and whose sum is 16. These two numbers are 8 and 8. (x2-16x+64)=(x-8)(x-8)
The question does not make sense because it has what appears to be an equation but which contains two "equals"!The question does not make sense because it has what appears to be an equation but which contains two "equals"!The question does not make sense because it has what appears to be an equation but which contains two "equals"!The question does not make sense because it has what appears to be an equation but which contains two "equals"!
It is: 4s = 64
Let x and y be the two numbers. We can set up a system of equations: x + y = 20 and xy = 64. By solving the first equation for y (y = 20 - x) and substituting into the second equation, we get x(20 - x) = 64. Simplifying this quadratic equation gives us x^2 - 20x + 64 = 0. Factoring this equation gives us (x - 16)(x - 4) = 0. Therefore, the two numbers are 16 and 4.
Let the page numbers be x and x+1. The product of two consecutive numbers is x(x+1). Given that the product is 4160, we have the equation x(x+1) = 4160. By solving this quadratic equation, we find that the page numbers are 64 and 65.