To be divisible by 5, the last digit must be 0 or 5. The last digit of 305 is 5, so it is divisible by 5.
Not evenly. You get 43.2 as the answer. To be divisible by 10, the last digit must be 0 The last digit of 432 is 2 which is not 0, so it is not divisible by 10.
There can be no such number. If it is divisible by 5 and 6it must be divisible by 6.
No. In order for a number to be divisible by 10, the ones digit must be zero (0).
Not necessarily. For example, the number 56 ends in a 6 but is not divisible by six. To check if a number is divisible by six, the number must be divisible by both 2 and 3. To check this, the last digit must be even and the sum of the digits must be divisible by three. If the number meets these conditions, it is in fact divisible by six.
To be divisible by 5, the last digit must be 0 or 5. The last digit of 305 is 5, so it is divisible by 5.
yes 552 is divisible by 6 and the result is 92... to find out if a number is divisible by 6 then that number must be divisible by 2 and 3.. 1.If a number is divisble by three then the last digit must be divisible by 2 (so that the last digit must be 0,2,4,6,8) in this number the last digit is 2 so that it is divisible by 2 2.If a number is divisble by 3 then the sum of its digit must be divisible by 3. In this case the sum of the digits of 552 is 5+5+2= 12 and 12 is divisible by 3.... If this two rules fit in then that number is divisible by 6
Not evenly. You get 43.2 as the answer. To be divisible by 10, the last digit must be 0 The last digit of 432 is 2 which is not 0, so it is not divisible by 10.
To be divisible by 5, the last digit must be 0 or 5. The last digit of 28 is neither 0 nor 5, so it is not divisible by 5.
There can be no such number. If it is divisible by 5 and 6it must be divisible by 6.
No. In order for a number to be divisible by 10, the ones digit must be zero (0).
yes ,5280 is divisible by 2 . as, last digit must even to make the number divisible by 2 . 5280 on division by 2 is equal to 2640 .
No. If any number is divisible by 5 and 6, it must also be divisible by 30, which means that it must end with a zero.
Not necessarily. For example, the number 56 ends in a 6 but is not divisible by six. To check if a number is divisible by six, the number must be divisible by both 2 and 3. To check this, the last digit must be even and the sum of the digits must be divisible by three. If the number meets these conditions, it is in fact divisible by six.
You test if the last two digits are divisible by 4. If the digit in the tens' place is odd, the digit in the units place must be 2 or 6. If the digit in the tens' place is even, the digit in the units place must be 0, 4 or 8.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 926 is a 6 which is NOT a 0, so 936 is NOT divisible by 10.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 195 is a 5 which is NOT a 0, so 195 is NOT divisible by 10.