Not sure what the question means, unless it is meant to refer to 3-dimensional shapes.
If so, some answers are:
a cylinder,
a cone,
a section of a sphere,
an ellipsoid with two equal axes intersected by a plane defined by those axes,
a symmetric paraboloid intersected by a plane perpendicular to its axis of symmetry,
a torus (doughnut) intersected by a plane perpendicular to its "main" radius.
A polyhedron.
They are closed 3-dimensional shapes with polygonal faces.
A rhombus is a two dimensional figure while the concept of {faces, vertices and edges} is relevant to 3-dimensional shapes.
They are both 3 dimensional shapes with faces that are polygons.
Polyhedra (plural; singular = polyhedron)
No, two dimensional shapes do not have faces
A polyhedron.
Bases are faces but faces are not necessarily bases.
No. A sphere is a three dimensional shape which has no polygonal faces. Similarly an ellipsoid, a torus, a paraboloid, hyperboloid etc are 3-D shapes with no polygonal faces.
Cylinder
They are closed 3-dimensional shapes with polygonal faces.
a cone
triangular pyramaid
A three dimensional shape bounded by plane (flat) faces is a polyhedron.
the answer really is 6there are 6 faces in a three-dimensional model
A rhombus is a two dimensional figure while the concept of {faces, vertices and edges} is relevant to 3-dimensional shapes.
They are both 3 dimensional shapes with faces that are polygons.