eihrtjigjekhejklhjmtknmkhrmtntkrtjtyhr
many ... any number x so that (x+2)/x, x>2
1. The divisor is the second number in a division problem. For instance 6 / 3 = 2. In this example, the divisor is 3. If you have a divisor of X, then the largest remainder possible is X-1. This is because if you had one more number in the remainder, it would form a complete count, and the remainder would go away. In the case of 2 as your divisor, think of the number 11. 11 / 2 has a remainder of 1. However, if you had one more in the remainder, you'd have 2, and that would be a complete division. (Also, the number you have to be 12.) And there would be no remainder.
Apparently, you're only using whole numbers in your division. In that case, the largest possible remainder is two (2).
There are several parts to a division problem. It is easy to see them with this example. 16 divided by 3 is 5 with a remainder of 1. The number 16 is the dividend and 3 is the divisor. The 5 is the quotient and the 1 is the remainder. To see that the answer of a division problem such as this is correct, just multiply. The divisor multiplied by the quotient plus the remainder is the dividend. So 3x5+1=16 as desired. Of course sometimes you have a problem like 8 divided by 2=4. In this case 8 is the dividend and 2 is the divisor. The number 4 is the quotient. The difference here is there is no remainder.
eihrtjigjekhejklhjmtknmkhrmtntkrtjtyhr
boomboom it goes in 2 funky times
many ... any number x so that (x+2)/x, x>2
11.6667
1. The divisor is the second number in a division problem. For instance 6 / 3 = 2. In this example, the divisor is 3. If you have a divisor of X, then the largest remainder possible is X-1. This is because if you had one more number in the remainder, it would form a complete count, and the remainder would go away. In the case of 2 as your divisor, think of the number 11. 11 / 2 has a remainder of 1. However, if you had one more in the remainder, you'd have 2, and that would be a complete division. (Also, the number you have to be 12.) And there would be no remainder.
Apparently, you're only using whole numbers in your division. In that case, the largest possible remainder is two (2).
2 with remainder 7.63 ÷ 28 = 2 with remainder 7.
The quotient. In the problem 7 / 2 = 3 (+1) The 7 is the "dividend"; the 2 is the "divisor": the 3 is the "quotient" and the 1 is the "remainder".
2.8636
There are several parts to a division problem. It is easy to see them with this example. 16 divided by 3 is 5 with a remainder of 1. The number 16 is the dividend and 3 is the divisor. The 5 is the quotient and the 1 is the remainder. To see that the answer of a division problem such as this is correct, just multiply. The divisor multiplied by the quotient plus the remainder is the dividend. So 3x5+1=16 as desired. Of course sometimes you have a problem like 8 divided by 2=4. In this case 8 is the dividend and 2 is the divisor. The number 4 is the quotient. The difference here is there is no remainder.
Yes, 31.5. So it is with a remainder.
40