The question cannot be answered unless you assume that
although there are no grounds for assuming so.
In that case, the perimeter is 2*(2.5 + 2) = 9 units of length and area = 2.5*2 = 5 square units.
Its perimeter is: 2*(10+2.5) = 25 m because its length is 25/2.5 = 10 m
40
Length = 7.5 cm Width = 5 cm Check:- Perimeter = 7.5+7.5+5+5 = 25 cm Area = 7.5*5 = 37.5 square cm
Multiply width by length to get the area. The simplest thing is to realize that the square root of 25 is 5, so it could be 5 feet on each side.
To find the width of the rectangle, we need to subtract twice the length from the perimeter. Given that the length is 25 centimeters and the perimeter is 84 centimeters, twice the length would be 50 centimeters. Subtracting 50 from 84 gives us a width of 34 centimeters for the rectangle.
For a start at this question, find out how wide this rectangle must be. area (250) = length (25) x width (???) The area of a rectangle is its length times its width. We should divide the area by the length (25) to get the width. The answer is 10. Then we know that each long side is 25 and each short side is 10. We know that in a rectangle, the long sides are the same length and the short sides are the same width. In order to get the perimeter, we add 25 and 25 and 10 and 10. We get 70. So the perimeter is 70.
Its perimeter is: 2*(10+2.5) = 25 m because its length is 25/2.5 = 10 m
40 meters.
perimeter = 2 x (width + length) area = width x length If area = perimeter then: width x length = 2 x width + 2 x length width x length - 2 x length = 2 x width length x (width - 2) = 2 x width length = 2 x width / (width - 2) So any rectangle with length and width that satifies the above will work, for example: width = 2.5, length = 10, area: 2.5 x 10 = 25; perimeter: 2x(2.5+10) = 2x12.5 = 25 width = 3, length = 6, area: 3x6 = 18; perimeter: 2x(3+6) = 2x9 = 18 width = 4, length = 4, area: 4x4 = 16; perimeter: 2x(4+4) = 2x8 = 16 By making the length dependent on the width, the width must be at least 2. Once the 4x4 square has been reached, the width becomes larger than the length, but the pair will also be given if the width is the smaller dimension, for example, a width of 6 gives a length of 2 x 6 / (6 - 2) = 12 / 4 = 3, which matches the length of 6 being given by a width of 3.
40
Length = 7.5 cm Width = 5 cm Check:- Perimeter = 7.5+7.5+5+5 = 25 cm Area = 7.5*5 = 37.5 square cm
Multiply width by length to get the area. The simplest thing is to realize that the square root of 25 is 5, so it could be 5 feet on each side.
The dimensions are length 50 yards and width 25 yards
To find the width of the rectangle, we need to subtract twice the length from the perimeter. Given that the length is 25 centimeters and the perimeter is 84 centimeters, twice the length would be 50 centimeters. Subtracting 50 from 84 gives us a width of 34 centimeters for the rectangle.
Let the length be x:- Perimeter = 2(x+25) = 122 inches 2x+50 = 122 2x = 122-50 2x = 72 x = 36 Check: 36+36+25+25 = 122 inches Area = 36*25 = 900 square inches
To find the perimeter of a rectangle simply add the length and width then double your answer.
The perimeter of a square, if it has an area of 25 cm, is: 20 cm