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Please solve this x plus ln x-3 -4 0 Thank you?
If you mean: x-3-4 = 0 then x = 7 I mean x + ln (x-3) - 4 =0
What does (3x-1)(x 3)0 equal?
If you mean: (3x-1)(x+1) = 0, then it is 3x squared+2x-1 = 0. Its solutions are: x = 1/3 or x = -1.
Solve x2 plus x - 6 equals 0?
x2 + x - 6 = 0 x2 + 3x - 2x - 6 = 0 x(x+3) -2(x+3) = 0 so (x+3)(x-2) = 0 so x+3 = 0 or x-2 = 0 so that x = -3 or x = 2
What are the coordinates of the roots for 8x2 - 64x 120 0?
If you mean: 8x2-64x+120 = 0 then x = 3 or x = 5
How do you solve 5x2 plus 15x equals 0?
5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3
Please solve this x plus ln x-3 -4 0 Thank you?
If you mean: x-3-4 = 0 then x = 7 I mean x + ln (x-3) - 4 =0
Is 0 3 a solution to the equation y x 3?
If you mean: y+x = 3 then the solutions are (0, 3) and (3, 0)
What does (3x-1)(x 3)0 equal?
If you mean: (3x-1)(x+1) = 0, then it is 3x squared+2x-1 = 0. Its solutions are: x = 1/3 or x = -1.
What does -3x² mean when x equals -3?
0
Solve x2 plus x - 6 equals 0?
x2 + x - 6 = 0 x2 + 3x - 2x - 6 = 0 x(x+3) -2(x+3) = 0 so (x+3)(x-2) = 0 so x+3 = 0 or x-2 = 0 so that x = -3 or x = 2
X is between negative three and zero- inclusive. - What does the 'inclusive' part mean?
It means X can also be equal to -3 or 0. -3 >= X >= 0 means "X is between negative three and zero- inclusive" -3 > X > 0 means "X is between negative three and zero" = =
What are the coordinates of the roots for 8x2 - 64x 120 0?
If you mean: 8x2-64x+120 = 0 then x = 3 or x = 5
How do you solve 5x2 plus 15x equals 0?
5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3
What is the solution for x 2 plus 5x plus 6 0?
If you mean: x2+5x+6 = 0 then the solutions are x = -3 and x = -2
What is y-4x plus 3 in standard form?
If you mean y = -x+3 then it is x+y-3 = 0 in standard form
What values of x will make the polynomial 0 if its factors are x - 6 and x - 3?
If a polynomial has factors x-6 and x-3 it will equal 0 if either factor equals 0 since the other factor then would be multiplied by 0. ie. 0 * (x-6)=0 and 0 * (x-3)=0. so x=3 or 6
How do you solve 2x2-x-3 equals 0?
2x2-x-3 = 0= 4 - x - 3 = 0= 1 - x = 0= 1 = xTherefore x = 1
