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What is the equation of a quadratic formula that has answers of -4 and 3?
The roots of the equation are -4 and 3. Simplest solution is (x +4 )(x - 3) which multiplies out as x^2 + x - 12 = 0
What is the solution of a equation derived from an original equation that is not a solution of the original equation?
x = 00 reduces to x = 0/0. Both are undefined, and thus cannot be considered "equal". Other than that, nothing.
Which ordered pair is a solution to the equation y - 2x 6?
For example, if you have (0, 6) or (3, 1). Which of them is a solution to y - 2x = 6? Check (0, 6): y - 2x = 6, substitute 0 for x, and 6 for y into the equation 6 - 2(0) =? 6 6 - 0 =? 6 6 = 6 True, then (0, 6) is a solution. Check (3, 1): y - 2x = 6, substitute 3 for x, and 1 for y into the equation 1 - 2(3) =? 6 1 - 6 =? 6 -5 = 6 False, then (3, 1) is not a solution.
Which equation has solution x -3?
The equation that has the solution x = -3, is, precisely:x = -3 If you want anything more fancy, you can add some number (the same number to both sides), multiply by some number (the same number to both sides), etc.
How do you sovle f(x)x2-9?
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Which equation has the solution set 1 and 3?
An equation with the solution set 1 and 3 can be written in factored form as (x-1)(x-3) = 0. When expanded, this equation becomes x^2 - 4x + 3 = 0. Therefore, the equation x^2 - 4x + 3 = 0 has the solution set 1 and 3.
What is the solution set of the equation 10x2-x-3 equals 0?
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What is the solution to a quadratic equation?
There are 2 (main) ways you can find the solution to a quadratic equation:Factorisation: If you take, for example, the equation (x-3)(x-2) = 0. Either (x-3) or (x-2) must equal 0 for the equation to be true: you then have x-3 = 0 (i.e. x = 3) and x-2 = 0 (i.e. x = 2). These are your solutions to the equation. If you have an equation in the form (say) x2+x-12 = 0, you can find that this is equivalent to (x-3)(x+4) = 0, so x = 3 or x = -4.The magic formula: If the equation won't factorise, or you can't see how it would, there is a formula you can use to give you both values of x: for any equation ax2+bx+c = 0, x = (-b±√(b2-4ac))/2a. The two values of x come from the ±: one uses a plus and the other a minus.
What is the equation of a quadratic formula that has answers of -4 and 3?
The roots of the equation are -4 and 3. Simplest solution is (x +4 )(x - 3) which multiplies out as x^2 + x - 12 = 0
What is the solution set for the equation x2 - x - 6 0?
X2 - X - 6 = 0what two factors of - 6 add up to - 1 ?(X + 2)(X - 3)============(- 2, 0 ) and (3, 0 )------------------------------solution set of points
Does a solution to an equation make the equation true or false?
A solution to an question makes the equation true. For example a solution to the equation 3x = x + 6 is x = 3, since 3(3) = 3+6.
What is an example of 0 as a solution for an equation?
Here is an example: x + 5 = 5If you subtract five from both sides, you get x = 0, which is an example of getting 0 as a solution for an equation.
Does an equation always have one solution?
Only a linear equation in one variable x , which is an equation of the form ax + b = 0, (where a is different than 0), has only one solution. The solution is: x = -b/a
-4 is a solution of which equation?
How about x+4 = 0 ?
How many solutions does the equation 0x2 x 3 have?
I assume you mean...,0X2 * 30 * 3= 0=====Only this solution
Show whether 0 3 is the solution of the linear system below 2x plus y equals -3 x plus 2y equals 8?
For (x, y) = (0, 3) the first equation gives: 2*0 + 3 = -3 that is, +3 = -3 which is FALSE. So (0, 3) is not a solution.
What is the solution of a equation derived from an original equation that is not a solution of the original equation?
x = 00 reduces to x = 0/0. Both are undefined, and thus cannot be considered "equal". Other than that, nothing.
