It is: 4*(q+p)
p divided by q.
1)p->q 2)not p or q 3)p 4)not p and p or q 5)contrudiction or q 6)q
When: p=12 and q=3 Then when: p=76 and so q=19 Because: 12/3=4 and 76/19=4
Suppose the roots a quadratic, in the form ax2 + bx + c = 0, are p and q. Then p + q = -b/a and pq = c/a
4(p + q), or 4p + 4q
P! / q!(p-q)!
It is: 4*(q+p)
p divided by q.
1)p->q 2)not p or q 3)p 4)not p and p or q 5)contrudiction or q 6)q
4 quarters in a dollar
When: p=12 and q=3 Then when: p=76 and so q=19 Because: 12/3=4 and 76/19=4
The answer depends on what p and q are!
For this problem, assume q is 100. So, if p is 40 percent, that would mean 40/100 which equals .4 or 40 percent. So, 100/40 equal 2.5 or 250 percent. If p is 40 percent of q, then q is 250 percent of p.
It means the statement P implies Q.
Suppose the roots a quadratic, in the form ax2 + bx + c = 0, are p and q. Then p + q = -b/a and pq = c/a
A rational number is any number of the form p/q where p and q are integers and q is not zero. If p and q are co=prime, then p/q will be rational but will not be an integer.