p divided by q.
a rational number
The sum of p and q means (p+q). The difference of p and q means (p-q).
If the coordinates of a point, before reflection, were (p, q) then after reflection, they will be (-p, q).
No, the statement "not(p and q)" is not equal to "(not p) or q." According to De Morgan's laws, "not(p and q)" is equivalent to "not p or not q." This means that if either p is false or q is false (or both), the expression "not(p and q)" will be true. Therefore, the two expressions represent different logical conditions.
1)p->q 2)not p or q 3)p 4)not p and p or q 5)contrudiction or q 6)q
P! / q!(p-q)!
It means the statement P implies Q.
a rational number
a rational number
Converse: If p r then p q and q rContrapositive: If not p r then not (p q and q r) = If not p r then not p q or not q r Inverse: If not p q and q r then not p r = If not p q or not q r then not p r
The sum of p and q means (p+q). The difference of p and q means (p-q).
q + p
Not sure I can do a table here but: P True, Q True then P -> Q True P True, Q False then P -> Q False P False, Q True then P -> Q True P False, Q False then P -> Q True It is the same as not(P) OR Q
If p = 50 of q then q is 2% of p.
If you mean, (by rational form), in the form "p/q", let p= -2 and q = 1
If p then q is represented as p -> q Negation of "if p then q" is represented as ~(p -> q)
If the coordinates of a point, before reflection, were (p, q) then after reflection, they will be (-p, q).