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csc = 1/sin csc (74o) = 1/sin(74o) = 1/0.9613 = 1.0403
From math class, some trigonometric identities: cot x = 1/tan x csc x = 1/sin x sec x = 1/cos x There are no built-in cot or csc formulas, so use the above. Remember that these give errors when tan x, sin x, or cos x are equal to 0.
The integral for csc(u)dx is -ln|csc(u) + cot(u)| + C.
cot(x)=1/tan(x)=1/(sin(x)/cos(x))=cos(x)/sin(x) csc(x)=1/sin(x) sec(x)=1/cos(x) Therefore, (csc(x))2/cot(x)=(1/(sin(x))2)/cot(x)=(1/(sin(x))2)/(cos(x)/sin(x))=(1/(sin(x))2)(sin(x)/cos(x))=(1/sin(x))*(1/cos(x))=csc(x)*sec(x)
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The derivative of csc(x) is -cot(x)csc(x).
How is it possible that the value of cosecant is less than 1 (2/7)?
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Since sin(a)=opposite/hypotenuse, the reciprocal function is that function which is equal to hypotenuse/opposite. This is "cosecant", or csc(a). The reciprocal of sin(a) is csc(a). I will solve all your math problems. Check my profile for more info.
∫cscxcotx*dx∫csc(u)cot(u)*du= -csc(u)+C, where C is the constant of integrationbecause d/dx(csc(u))=-[csc(u)cot(u)],so d/dx(-csc(u))=csc(u)cot(u).∫cscxcotx*dxLet:u=xdu/dx=1du=dx∫cscucotu*du= -csc(u)+CPlug in x for u.∫cscxcotx*dx= -csc(x)+C
csc = 1/sin csc (74o) = 1/sin(74o) = 1/0.9613 = 1.0403
csc(74) = 1.0403 (rounded)
That depends on the value of the angle, theta. csc is short for "cosecans", and is the reciprocal of the sine. That is, csc theta = 1 / sin theta.