To find the mean from a raw score, z-score, and standard deviation, you can use the formula: ( \text{Raw Score} = \text{Mean} + (z \times \text{Standard Deviation}) ). Rearranging this gives you the mean: ( \text{Mean} = \text{Raw Score} - (z \times \text{Standard Deviation}) ). Simply substitute the values of the raw score, z-score, and standard deviation into this formula to calculate the mean.
78
A z-score requires the mean and standard deviation (or standard error). There is, therefore, not enough information to answer the question.
Bob scored 300 or 700.
z-score of a value=(that value minus the mean)/(standard deviation). So a z-score of -1.5 means that a value is 1.5 standard deviations below the mean.
To find the mean from a raw score, z-score, and standard deviation, you can use the formula: ( \text{Raw Score} = \text{Mean} + (z \times \text{Standard Deviation}) ). Rearranging this gives you the mean: ( \text{Mean} = \text{Raw Score} - (z \times \text{Standard Deviation}) ). Simply substitute the values of the raw score, z-score, and standard deviation into this formula to calculate the mean.
score of 92
A negative Z-Score corresponds to a negative standard deviation, i.e. an observation that is less than the mean, when the standard deviation is normalized so that the standard deviation is zero when the mean is zero.
A z-score cannot help calculate standard deviation. In fact the very point of z-scores is to remove any contribution from the mean or standard deviation.
No. The standard deviation is not exactly a value but rather how far a score deviates from the mean.
The standard deviation.z-score of a value=(that value minus the mean)/(standard deviation)
78
mean is 218 with a standard deviation of 16
z-score of a value=(that value minus the mean)/(standard deviation)
z-score of a value=(that value minus the mean)/(standard deviation)
z-score of a value=(that value minus the mean)/(standard deviation)
A z-score requires the mean and standard deviation (or standard error). There is, therefore, not enough information to answer the question.