It's K!
Points: (k, 3h) and (3k, h) Slope: h-3h/3k-k = -2h/2k => -h/k Equation: y-3h = -h/k(x-k) => ky-3hk = -h(x-k) => ky = -hx+hk+3hk Equation in its general form: hx+ky-4hk = 0
when the function is in vertex form: y = a(x - h)2 + k, the point (h, k) is the vertex.
A fraction of the form (6*k)/k for any k.
When you have the equation y-k=a(x-h)^2. You know the vertex=(h,k) And the axis of symmetry goes through the vertex; so h=the axis of symmetry. Say you have the axis is x=5. Thus h=5. Now all you have to do is plug in the two points in the eqaution and use a solution (try substitution) to solve for a. Then plug it back in to get k. EX: x=5 (6,1) and (7,4) 1-k=a(6-5)^2 and 4-k=a(7-5)^2 1-k=a 4-k=4a 1-a=k *now substitute* 4-(1-a)=4a 4-1+a=4a 3=3a a=1 (go back and plug in a) k=1-1 k=0 The answer is: y=(x-5)
What does 14 K and H with a circle in it mean
K - Eighth Avenue Local - ended in 1988.
K is the eight consonant in the alphabet!
A parabola with vertex (h, k) has equation of the form: y = a(x - h)² + k → vertex (k, h) = (3, 5), and a point on it is (-1, 6) → 6 = a(-1 - 3)² + 5 → 6 = a(-4)² + 5 → 1 = 16a → a = 1/16 → The coefficient of the x² term is 1/16
For a parabola with a y=... directrix, it is of the form: (x - h)^2 = 4p(y - k) with vertex (h, k), focus (h, k + p) and directrix y = k - p With a focus of (3, 6) and a directrix of y = 4, this means: (h, k + p) = (3, 6) → k + p = 6 y = k - p = 4 → k = 5, p = 1 (solving the simultaneous equations) → vertex is (3, 5) → parabola is (x - 3)^2 = 4(y - 5) which can be rearranged into y = 1/4 x^2 - 3/2 x + 29/4
facebook need to be off.
1-f-d-h-h-h-0-9-7-7-6-k-s-
'K' is the eight consonant in the alphabet.A B(1) C(2) D(3) E F(4) G(5) H(6) I J(7) K(8) L M N O P Q R S T U V W X Y Z
Something we won't say on WikiAnswers.
H- Hug K- Kiss D- Date
No such model number in my references. Do you mean the H&K G3?
It means f~k you b!t(h