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logarithms are the reverse form of squares. there are different ways to solve logarithms. log b 256=4 would be b4=256. You just rotate the variables, b to the left side, 256 to the right side, and the 4 goes up. To expand a logarithm, log5 (7*11) would be log5 (7)+log5 (11) In a division logarithm, log5 (7/11), you would say log5 (7)-log5 (11) Multiplication is added, and division is subtracted. Hope that helps a little:].
x is approximately 11.18
logbase5 of x =z x=5^z
To solve the equation 3log5 125 - log2 8 = x, you can use the properties of logarithms. First, simplify the logarithmic expressions: 3log5 125 simplifies to log5 (125^3), and log2 8 simplifies to log2 (2^3). This gives you log5 15625 - log2 8 = x. Then, you can combine the logarithms using the quotient rule to get log5 (15625/8) = x. Finally, simplify the expression inside the logarithm to get x = log5 1953.125.
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