o.62
logarithms are the reverse form of squares. there are different ways to solve logarithms. log b 256=4 would be b4=256. You just rotate the variables, b to the left side, 256 to the right side, and the 4 goes up. To expand a logarithm, log5 (7*11) would be log5 (7)+log5 (11) In a division logarithm, log5 (7/11), you would say log5 (7)-log5 (11) Multiplication is added, and division is subtracted. Hope that helps a little:].
x is approximately 11.18
logbase5 of x =z x=5^z
Your calculator won't usually have a function to calculate logs in base 5 or base 8 directly, but this can easily be solved. For example: log5125 = log 125 / log 5 (taking both logs in base 10, or both logs in base e) In this particular case, you can also solve the equation mentally - you don't even need a calculator! Just use the definition of a log: "To what power must I raise 5 to get 125?" The answer to this is, by definition, log5125. Similarly with log28.
The value of (\log 5) depends on the base of the logarithm. If it is the common logarithm (base 10), (\log_{10} 5 \approx 0.699). If it is the natural logarithm (base (e)), (\ln 5 \approx 1.609). For base 5, (\log_5 5 = 1).
log5(100) = 2.861353116 to nine decimal places.
log5(2) + log5(10) - log5(4) = log5(20/4) = log5(5) = 1
log5 20 + log5 10 - 3log5 2 = log5 [(20*10)/(2^3)] = log5 25 = 2 (log5 5) = 2
logarithms are the reverse form of squares. there are different ways to solve logarithms. log b 256=4 would be b4=256. You just rotate the variables, b to the left side, 256 to the right side, and the 4 goes up. To expand a logarithm, log5 (7*11) would be log5 (7)+log5 (11) In a division logarithm, log5 (7/11), you would say log5 (7)-log5 (11) Multiplication is added, and division is subtracted. Hope that helps a little:].
log5 +log2 =log(5x2)=log(10)=log10(10)=1
No, it is not.
x is approximately 11.18
1.268293446
logbase5 of x =z x=5^z
assuming that this means log5125=x, x=3.
e=mc2
Your calculator won't usually have a function to calculate logs in base 5 or base 8 directly, but this can easily be solved. For example: log5125 = log 125 / log 5 (taking both logs in base 10, or both logs in base e) In this particular case, you can also solve the equation mentally - you don't even need a calculator! Just use the definition of a log: "To what power must I raise 5 to get 125?" The answer to this is, by definition, log5125. Similarly with log28.