8y/y + 2 + 16/y + 2 = 8 + 2 + 16/y +2 = 12 + 16/y = 4(3 + 4/y) or 4/y*(3y + 4)
x = -2 and y = 3
That is irrelevant, there is not possible way y=xy, and there is no possible way xy=x.
The variable 'x' would equal (8-y)/2. The variable 'y' would equal 8-2x.
(-3,-4)
2y
(x^2 - y^2)
y = 2
8y/y + 2 + 16/y + 2 = 8 + 2 + 16/y +2 = 12 + 16/y = 4(3 + 4/y) or 4/y*(3y + 4)
x = -2 and y = 3
That is irrelevant, there is not possible way y=xy, and there is no possible way xy=x.
you need to know the x or y value
If x+y = 3 and y times x = 2 then y = 1.
The variable 'x' would equal (8-y)/2. The variable 'y' would equal 8-2x.
4y+y=10 5y=10 y=2
Only when X or Y = 0 That is because (x + y) squared = x^2 + 2xy + y^2 x^2 + 2xy + y^2 = x^2 + y^2 when x or y = 0
-x+y = 1 -2+y = -2 y = 1+x y = -2+2 => y = 0 By sustituting the values of x and y can be found x = -1 and y = 0 Remember that a minus from a minus is equal to a plus. So - -1+0 = 1