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F = For Y = Your D = Descrition i think lol
X + Y (X + Y) ^2 = (X+Y)(X+Y) Factor = (X + Y)
(y + 8)(y - 7)
To factor out the expression: x2y-y3 First factor out one "y": y(x2-y2) The expression x2-y2 is a difference of squares, which factors as well: (y)(x-y)(x+y) This is the simplest factoring of the original expression.
y^(3) - 2y^(2) + 4y Factor out 'y' Hence y(y^2 - 2y + 4) This will not factor any further.
That means that if "x" varies by a certain factor, "y" will vary by the same factor. For example, if "x" is double, then "y" will also double.
F = For Y = Your D = Descrition i think lol
X + Y (X + Y) ^2 = (X+Y)(X+Y) Factor = (X + Y)
1 and Y
GCF(Y, Y) = Y.
The GCF is Y.
The GCF is Y.
All you can do to factor that expression is to divide both terms by y: y2 + 4y = y(y + 4)
GCF(Y, Y) = Y.
y(y-3)(y+3)
(y + 8)(y - 7)
do you mean 2x + 2y? and if you do you would get this 2(x+y) but that's as far as you can go seeing as their are no more common terms You factor x^2+y^2 like this. x^2+y^2=(x+y)(x-y) +2y^2 or You can do (x+iy)(x-iy)