x2 -y2 +4y-4=(x+y)(x-y)+4y-4
7(3y-2)-(-4y+9)
4x-4y-ty+xt = 4x+tx-4y-ty = x(4+t) - y(4+t) = (x-y)*(4+t)
The value of y in the equation -2x plus 4y -4, is 1 plus x/2.
y^3 + y^2 - 6 (y+2) (y-3) i think
4(x+y)^2
y(3y^2 - 12y + 4)
(13x^2 - 4y)(2x^2 - 5y)
2y + 1
9y cubed plus 2y squared
4(y - 3)(y + 3)
y^(3) - 2y^(2) + 4y Factor out 'y' Hence y(y^2 - 2y + 4) This will not factor any further.
The greatest common factor in the two terms is [ 4y ].The factored form of the expression is4y (y + 7x)
4y2 + 16y + 16 = 4(y2 + 4y + 4) = 4(y2 + 2y + 2y + 2) = 4[y(y + 2) + 2(y + 2)] = 4(y + 2)2
Factor out the 4. The answer is y-3/y+3
x2 -y2 +4y-4=(x+y)(x-y)+4y-4
xy plus 2x plus 4y plus 8 or (xy+2x) + (4y+8) or x(y+2) + 4(y+2) or (x+4)(y+2)