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Does a 40 sided polygon have 6840 diagonals?
The sum of the angles of a regular n-sided polygon is equal to (n - 2) x 180 degrees.Therefore, the sum of the angles of a regular 40-sided polygon (tetradecagon) is equal to (40 - 2) x 180 = 6840 degrees. Therefore, 6840 refers to the sum of the degrees, not the number of diagonals.The number of diagonals of an n-sided polygon is given by n(n-3)/2. So a 40-sided polygon has 40*37/2=740 diagonals.
What is three consecutive integers whose sum is 117?
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
What is the sum expression for the sum of n and 5?
The sum of n and 5 is n+ 5
C program to find sum of 'n' number using function?
void main () { int no1, sum, n; clrscr() sum = 0; n = 1; printf("\n enter the number to which sum is to be generated"); scanf("%d",&no1); while(n<=no1) { sum=sum+n; n=n+1 } printf("\n the sum of %d = %d, no1, sum"); getch (); }
What is -n equals 40?
If -n = 40 then n = -40.
What is the sum of the first forty positive integers?
The sum of the first forty positive integers can be calculated using the formula for the sum of an arithmetic series, which is (n/2)(first term + last term) where n is the number of terms. In this case, the sum is (40/2)(1 + 40) = 820.
What is the sum of the interior angle measures of a 40- sided convex polygon?
The sum of the interior angles of a convex polygon with n sides is given by (n-2)x180o. So for a 40 sided polygon n=40; thus (40-2)x180o = 38x180o = 6840o.
Does a 40 sided polygon have 6840 diagonals?
The sum of the angles of a regular n-sided polygon is equal to (n - 2) x 180 degrees.Therefore, the sum of the angles of a regular 40-sided polygon (tetradecagon) is equal to (40 - 2) x 180 = 6840 degrees. Therefore, 6840 refers to the sum of the degrees, not the number of diagonals.The number of diagonals of an n-sided polygon is given by n(n-3)/2. So a 40-sided polygon has 40*37/2=740 diagonals.
What is the sum of the interior angles of a polygon with 40 sides?
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. 6840 degrees
Interior angles of a 40-gon?
The sum of the interior angles of an n-gon is (n-2)*180 degrees. So, for a 40-gon, the sum of the interior angles would be 38*180 = 6840 degrees. If the 40-gon was not regular that is as far as you could go. But if it was a regular n-gon, then all its interior angles are equal, and each would be of 6840/40 = 171 degrees.
What is three consecutive integers whose sum is 117?
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
What 5 consecutive numbers have the sum of 40?
Let's denote the five consecutive numbers as n, n+1, n+2, n+3, and n+4. The sum of these numbers is given by n + (n+1) + (n+2) + (n+3) + (n+4) = 5n + 10 = 40. Solving for n, we get n = 6. Therefore, the five consecutive numbers are 6, 7, 8, 9, and 10.
What is the sum expression for the sum of n and 5?
The sum of n and 5 is n+ 5
How many sides on a polygon with the sum of the interior angles is 6840?
If the polygon has n sides, the sum of the interior angles is (n - 2)*180 degrees. So (n - 2)*180 = 6840 (n - 2) = 6840/180 = 38 So n = 38 + 2 = 40 sides.
To write a program that calculates and prints the sum of all even numbers between 10 and 40 I have tried but i will waste characters showing it.?
In C: #include <stdio.h> int main(void) { int i, sum=0; for (i=10; i<=40; i+=2) { sum += i; } printf("%d\n", sum); return 0; }
C code that will give the sum of an entered input?
#include<stdio.h> #include<conio.h> main() { int n,sum=0; printf("enter n value"); scanf("%d",n); while(n!=0) { n=n/10; sum=sum+n; n=n%10; } printf("sum is=%d",sum }
C program to find sum of 'n' number using function?
void main () { int no1, sum, n; clrscr() sum = 0; n = 1; printf("\n enter the number to which sum is to be generated"); scanf("%d",&no1); while(n<=no1) { sum=sum+n; n=n+1 } printf("\n the sum of %d = %d, no1, sum"); getch (); }
