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A equals vf-vi divided by t?
(vf-vi)/ t is ?
What is the equation for average acceleration?
A equals Vf minus Vi divided by time equals triangle v divided by time
What is final speed divided by acceleration?
Final Velocity minus Initial Velocity (all together this is the change in velocity) divided by the average acceleration will give you the time it took for the object to reach that speed.(Vf - Vi) / Aaverage = Time
How to solve vf vi plus at equation steps?
To solve the equation vf = vi + at, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time, you first need to identify the values of vi, a, and t. Then, substitute these values into the equation and solve for vf by adding vi and the product of a and t. This equation is derived from the kinematic equation vf = vi + at, which relates the final velocity of an object to its initial velocity, acceleration, and time.
How is acceleration related to the distance and time elapsed?
acceleration cannot be calculated from these values alone unless one makes a few assumptions: Vf=final velocity Vi=initial velocity a=acceleration d=displacement t=time assume Vi=0 (Vf-Vi)/t=a Vf=at+Vi Vf**2=Vi**2+2ad (at)**2=2ad aatt=2ad att=2d a=2d/t**2
A equals vf-vi divided by t?
(vf-vi)/ t is ?
What is the equation for average acceleration?
A equals Vf minus Vi divided by time equals triangle v divided by time
What is the formula used to calculate the accelerating?
A=Vf-Vi/t Acceleration is the final velocity minus the initial velocity divided by the time it too to reach it
What is final speed divided by acceleration?
Final Velocity minus Initial Velocity (all together this is the change in velocity) divided by the average acceleration will give you the time it took for the object to reach that speed.(Vf - Vi) / Aaverage = Time
What is vi equals vf-at?
The equation vi = vf - at relates the initial velocity (vi), final velocity (vf), acceleration (a), and time (t) of an object moving with constant acceleration. This equation is derived from the kinematic equation vf = vi + at using algebraic manipulation.
How do you calculate beginning speed of an object?
The beginning speed of an object can be calculated using the equation: Vf = Vi + at where: Vf = final speed Vi = initial speed a = acceleration t = time You can rearrange the equation to solve for Vi: Vi = Vf - at
How to solve vf vi plus at equation steps?
To solve the equation vf = vi + at, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time, you first need to identify the values of vi, a, and t. Then, substitute these values into the equation and solve for vf by adding vi and the product of a and t. This equation is derived from the kinematic equation vf = vi + at, which relates the final velocity of an object to its initial velocity, acceleration, and time.
If the average speed of a car is 80mph and it started from rest what is its final speed?
Vavg = (Vi + Vf)/2 Vi = 0 Vavg = Vf/2 Vf = 2*Vavg Vavg = 80 Vf = 160
What is the relationship between work and motion?
Work is done when a force is applied to move an object over a distance. So, work leads to motion, as the application of force causes a change in the position of an object. The work done on an object is directly related to the distance over which the force is applied and the magnitude of the force.
How is acceleration related to the distance and time elapsed?
acceleration cannot be calculated from these values alone unless one makes a few assumptions: Vf=final velocity Vi=initial velocity a=acceleration d=displacement t=time assume Vi=0 (Vf-Vi)/t=a Vf=at+Vi Vf**2=Vi**2+2ad (at)**2=2ad aatt=2ad att=2d a=2d/t**2
What is an equation in physics?
f=ma vf=vi+at s=vi+1/2at
A car of mass 1200 kg is being towed horizontally on the end of a horizontal cable the car accelerates uniformly from rest to a speed of 15ms-1 in a distance of 75m show that the accleration of t?
A car of mass 1200 kg is being towed horizontally on the end of a horizontal cable the car accelerates uniformly from rest to a speed of 15ms-1 in a distance of 75m show that the accleration of t?Motion formulasvfinal = vinitial + acceleration * timevf = vi + a * tvf - vi = a * tt = (vf - vi ) ÷ aaverage velocity = (vi + vf) ÷ 2distance = average velocity * timed = (vi + vf) ÷ 2tt = 2d ÷ (vi + vf)Set the 2 equations equal to t, equal to each other.(vf - vi ) ÷ a = 2d ÷ (vi + vf)This would look better as a proportion, but wiki doesn't copy symbols!Cross multiply and divide(vf - vi ) * (vi + vf) = 2*a*dvf2 - vi2 = 2*a*dvf2 = vi2 +2*a*dYour question:Mass = 1200KgDistance = 75mvi = 0 m/schange in velocity = (vf - vi) = 15m/s - 0 /s = 15m/s(vf - vi) = 15m/svf2 = vi2 + 2*a*dvi2 = 0vf2 = 2*a*d152 = 2*a*75 a = 1.5 m/svf = vi + att = (vf - vi)÷ at = 15m/s ÷ 1.5 m/s2 = 10 secondsForce = mass * acceleration F = 1200kg * 1.5 m/s2 =F = 1800 Newtons
