That's the formula for average acceleration.
vf or rather vf stands for final velocity
vi or rather vi stands for initial velocity
t stands for time.
(vf-vi)/ t is ?
A equals Vf minus Vi divided by time equals triangle v divided by time
Final Velocity minus Initial Velocity (all together this is the change in velocity) divided by the average acceleration will give you the time it took for the object to reach that speed.(Vf - Vi) / Aaverage = Time
Well, let's break it down nice and easy. To solve the equation vf = vi + at, you first subtract vi from both sides to isolate vf. Then, you multiply a by t and add the result to vi to find vf. Remember, take your time and enjoy the process of solving equations like this - it's just like painting a happy little picture!
acceleration cannot be calculated from these values alone unless one makes a few assumptions: Vf=final velocity Vi=initial velocity a=acceleration d=displacement t=time assume Vi=0 (Vf-Vi)/t=a Vf=at+Vi Vf**2=Vi**2+2ad (at)**2=2ad aatt=2ad att=2d a=2d/t**2
(vf-vi)/ t is ?
A equals Vf minus Vi divided by time equals triangle v divided by time
A=Vf-Vi/t Acceleration is the final velocity minus the initial velocity divided by the time it too to reach it
Final Velocity minus Initial Velocity (all together this is the change in velocity) divided by the average acceleration will give you the time it took for the object to reach that speed.(Vf - Vi) / Aaverage = Time
Yes recalling the first equation of motion ie Vf = Vi + at Here Vf is final velocity and Vi is the initial velocity. a the acceleration and t is the time Now taking at on the other side ie left side we get Vf - at = Vi This is what mentioned here.
The beginning speed of an object can be calculated using the equation: Vf = Vi + at where: Vf = final speed Vi = initial speed a = acceleration t = time You can rearrange the equation to solve for Vi: Vi = Vf - at
Well, let's break it down nice and easy. To solve the equation vf = vi + at, you first subtract vi from both sides to isolate vf. Then, you multiply a by t and add the result to vi to find vf. Remember, take your time and enjoy the process of solving equations like this - it's just like painting a happy little picture!
Vavg = (Vi + Vf)/2 Vi = 0 Vavg = Vf/2 Vf = 2*Vavg Vavg = 80 Vf = 160
1) Work input = Force * distance 2) Force = mass*acceleration 3) Acceleration = (Vf - Vi) ÷ time 4) Force = mass * [(Vf - Vi) ÷ time] 5) Distance = Average velocity * time 6) Average velocity = (Vf + Vi) ÷ 2 7) Distance = [(Vf + Vi) ÷ 2] * time Eq#4 * EQ #7 8) Work input = mass * [(Vf - Vi) ÷ time] * [(Vf + Vi) ÷ 2] * time Time cancels 9) Work input = mass * (Vf - Vi) * (Vf + Vi) ÷ 2 10)(Vf - Vi) * (Vf + Vi) = Vf^2 - Vi^2 11)Work input = mass * [Vf^2 - Vi^2] ÷ 2 12)Work input = mass *( Vf^2 ÷ 2) - mass * (Vi^2 ÷ 2) 13)Kinetic energy = ½ mass *velocity ^2 14) Change in KE = (½ mass * Vf ^2) - (½ mass * Vi ^2) Equation #12 = Equation #14 so 15)Work input = Change in KE 16)Work input = ∆ KE
acceleration cannot be calculated from these values alone unless one makes a few assumptions: Vf=final velocity Vi=initial velocity a=acceleration d=displacement t=time assume Vi=0 (Vf-Vi)/t=a Vf=at+Vi Vf**2=Vi**2+2ad (at)**2=2ad aatt=2ad att=2d a=2d/t**2
f=ma vf=vi+at s=vi+1/2at
A car of mass 1200 kg is being towed horizontally on the end of a horizontal cable the car accelerates uniformly from rest to a speed of 15ms-1 in a distance of 75m show that the accleration of t?Motion formulasvfinal = vinitial + acceleration * timevf = vi + a * tvf - vi = a * tt = (vf - vi ) ÷ aaverage velocity = (vi + vf) ÷ 2distance = average velocity * timed = (vi + vf) ÷ 2tt = 2d ÷ (vi + vf)Set the 2 equations equal to t, equal to each other.(vf - vi ) ÷ a = 2d ÷ (vi + vf)This would look better as a proportion, but wiki doesn't copy symbols!Cross multiply and divide(vf - vi ) * (vi + vf) = 2*a*dvf2 - vi2 = 2*a*dvf2 = vi2 +2*a*dYour question:Mass = 1200KgDistance = 75mvi = 0 m/schange in velocity = (vf - vi) = 15m/s - 0 /s = 15m/s(vf - vi) = 15m/svf2 = vi2 + 2*a*dvi2 = 0vf2 = 2*a*d152 = 2*a*75 a = 1.5 m/svf = vi + att = (vf - vi)÷ at = 15m/s ÷ 1.5 m/s2 = 10 secondsForce = mass * acceleration F = 1200kg * 1.5 m/s2 =F = 1800 Newtons