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To find the equation of the line passing through the points (-1, -3) and (2, 1), we first calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the points, we get ( m = \frac{1 - (-3)}{2 - (-1)} = \frac{4}{3} ). Using the point-slope form ( y - y_1 = m(x - x_1) ) with one of the points, say (-1, -3), the equation becomes ( y + 3 = \frac{4}{3}(x + 1) ), which simplifies to ( y = \frac{4}{3}x + \frac{1}{3} ).
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What equation represents a line parallel to the y axis and passes through the points 4 and 3?
A line that is parallel to the y-axis is a vertical line. The equation of a vertical line is of the form ( x = k ), where ( k ) is a constant. Since the line passes through the points ( (4, y) ) and ( (3, y) ), the line that is parallel to the y-axis and passes through these points would have the equation ( x = 4 ) or ( x = 3 ), depending on which point you choose.
What is the equation for a line that passes through the points (2-2) and (-422)?
If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
Which is not an equation of the line that passes through the points 1 1 and 5 5?
The equation for the given points is y = x+4 in slope intercept form
What is the equation of a line that passes through points -1 2 and 5 2?
It is y = 2.
Which of the following is the equation of a line that passes through the points (06) and (210)?
Answer this question…y = 2x + 6
Write the equation of the line that passes through the points 12 and 6 and 12 and -4?
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
How do you find the equation of a tangent line?
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
What is the equation of the line that passes through the points (-42) and (4-2)?
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
What is the equation of the line that passes through 1 5 and 4 11?
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
What is The graph of a line passes through the points (0 -2) and (6 0). What is the equation of the line?
Points: (0, -2) and (6, 0) Slope: 1/3 Equation of line: 3y = x-6
What is the equation for a line that passes through the points (2-2) and (-422)?
If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
Which is not an equation of the line that passes through the points 1 1 and 5 5?
The equation for the given points is y = x+4 in slope intercept form
What is the equation of a line that passes through points -1 2 and 5 2?
It is y = 2.
What equation of a line passes through the points 0'8 and 3'-1?
Y= -3x + 8
What is the equation of the line that passes through the points 5 2 and 5 7?
If the line passes through (5, 2) and (5, 7), then the x value stays constant for those two points, and since it is a line, the x value stays constant for the whole line, so the equation of the line isx = 5
If the equation of a line passes through the points (1, 3) and (0, 0), which form would be used to write the equation of the line?
Slope-intercept form
If a line passes through the points 2 4 and 3 2 the equation of the line is y 2 25x?
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