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If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
The equation for the given points is y = x+4 in slope intercept form
It is y = 2.
Answer this question…y = 2x + 6
Points: (-1, 2) and (5, 2) Slope: 0 Equation: y = 2
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
Points: (0, -2) and (6, 0) Slope: 1/3 Equation of line: 3y = x-6
The equation for the given points is y = x+4 in slope intercept form
If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
Y= -3x + 8
It is y = 2.
If the line passes through (5, 2) and (5, 7), then the x value stays constant for those two points, and since it is a line, the x value stays constant for the whole line, so the equation of the line isx = 5
Slope-intercept form
3