(- 3, 10) and (6, 7)
Need slope.
m = Y2 - Y1/X2 - X1
m = 7 - 10/6 - (- 3)
= - 1/3
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Now, take that nice set of points, (6, 7), and use the point slope form.
Y - Y1 = m(X - X1)
Y - 7 = -1/3(X - 6)
Y - 7 = (- 1/3)X + 2
Y = (- 1/3)X + 9
==============The equation of the line
The straight line equation works out as: 3y = x
y=2/5x
The equation works out as: 5y = 2x or as y = 2/5x
Points: (7, 3) (14, 6) (21, 9) Slope: 3/7 Equation: 7y=3x
The equation ( y = 2x ) represents a straight line where the y-coordinate is twice the x-coordinate. To determine points that lie on this line, you can substitute the x-values into the equation and check if the resulting y-values match. For example, points like (1, 2), (2, 4), and (0, 0) all satisfy the equation and lie on the line.
what is the slope of the line containing points (5-,-2) and (-5,3)? 2
What is the equation of the line containing the points (5, 2), (10, 4), and (15, 6)?y = (2/5)x
The straight line equation works out as: 3y = x
The straight line equation works out as: 3y = x
y=2/5x
Points: (14, 6) (21, 9) (7, 3) Slope of the line: 3/7 Equation of the line: 7y = 3x and it has no y intercept
The equation works out as: 5y = 2x or as y = 2/5x
Points: (7, 3) (14, 6) (21, 9) Slope: 3/7 Equation: 7y=3x
Points: (7, 3) (14, 6) (21, 9) Slope: 3/7 Equation: 7y=3x
Points: (6, -3) and (-4, -9) Slope: 3/5 Equation: 5y = 3x-33
Points: (3, 2) and (-9, 6) Slope: -1/3 Equation: 3y = -x+9
Points: (6, -3) and (-4, -9) Slope: 3/5 Equation: 5y = 3x-33