Is there a specific equation involved here? Otherwise, X and Y are unrelated. It's possible for Y to stay the same no matter what you do with X. In this case, when graphing it, you get a line going straight across. Every equation is different, and will cause Y to do different things when you change X.
If the reflection is over the x value, the x-value does not change.
Using the quadratic formula, you will find for the equation 6x² + 2x + k = 0: x = (-b ±√(b² - 4ac)) / 2a → x = (-2 ± √(2² - 4×6×k)) / (2×6) → x = (-2 ± √(4 - 4×6k)) / (2×6) → x = (-1 ± √(1 - 6k)) / 6 The value of the discriminant (b² - 4ac) affects the value of x: >0 → there are two real values of x; this happens when 1 - 6k > 0 → k < 1/6; =0 → there is one repeated root, ie a single value of x; this happens when k = 1/6 (making x = -1/6); <0 → there are two complex values of x; this happens when k > 1/6.
Yes, it can be the slope of an infinite number of lines. As long as the y-value goes down one for every time the x-value increases by one, the line has a slope of -1.
1/x (not a function though, since it's not defined for x=0). e^(-x) converges close to zero as x increases, would be a good choice.
if value is 1 then its 1, all depends upon value of x
The value of x is directly proportional to to the value of y.hence when the value of x increases the value of y decrteses and vice verse
When x is nearly zero,y increases in value.
7
If the slope is negative, y decreases as x increases. The slope goes from top-left of the graph (Quadrant II) to the lower-right of the graph (Quadrant IV).
If the equation is y= x+2, then y will increase 1 when x increases 1 lets say x is 1 y will be 3 if x is 2, y will be 4 y=2x+5 y will increase 2 every time x increases by 1 x=1 y would be7 x=2 y would be 9 So the number that is multiplied by x is what determines the change in y, the numbers that are added or subtracted don't matter. so y=7x y would change 7 every time x is changed 1 80x would mean that y changes 80 each time x changes by 1
Try it out. 20 - 3 = 17 20 - 4 = 16 The value decreases as x increases.
A positive gradient is a characteristic of a function whose value increases as the value of the argument increases. So, if y is a function, f(x), of x, then an increase in the value of x is accompanied by an increase in the value of y.
it increases
If a function Y is dependent on X. if X increases in value then Y also increases then we call this a positive relationship. If X increases in value then Y decreases or vice versa then we call this a negative relationship.
If the reflection is over the x value, the x-value does not change.
Using the quadratic formula, you will find for the equation 6x² + 2x + k = 0: x = (-b ±√(b² - 4ac)) / 2a → x = (-2 ± √(2² - 4×6×k)) / (2×6) → x = (-2 ± √(4 - 4×6k)) / (2×6) → x = (-1 ± √(1 - 6k)) / 6 The value of the discriminant (b² - 4ac) affects the value of x: >0 → there are two real values of x; this happens when 1 - 6k > 0 → k < 1/6; =0 → there is one repeated root, ie a single value of x; this happens when k = 1/6 (making x = -1/6); <0 → there are two complex values of x; this happens when k > 1/6.
Y would decrease in value as X increases in value.