The integer is 10.
The square root of 65 is between the integers of 8 and 9
Negative 64 is the square root of an integer. The square root of -64 is not an integer.
A principal square root is any square root that's answer is positive, and a perfect square root is a square root that's answer is an integer.
No, the square root of an integer will not always be an integer. It may or may not be. The square root of nine is three, both of which are integers. The square root of two is not an integer. In fact, it is not even a rational number.
The integer is 10.
√479 ≈ 21.89 √500 ≈ 22.36 Making 22 as the integer between them.
The square root of 65 is between the integers of 8 and 9
None. 1000 does not have an integer square root. 312 = 961 and 322 = 1024 and there is no integer between 31 and 32 so there can be no integer whose square is 1000.
The square root of an integer is a CYCLOTOMIC integer.
no.No. The square root of 5 is an irrational number. The two closest numbers with integer square roots are 4 (with a square root of 2) and 9 (with a square root of 3). Since there are no integers between 2 and 3 and 5 lies between 4 and 9, it's pretty evident that it can't have an integer square root.
Negative 64 is the square root of an integer. The square root of -64 is not an integer.
no, the square root of an integer will not always be another integer. take the integer 27, for example. the square root of 27 is about 5.1961, which is not an integer.No eg square root of 17 is 4.1231056...
The square root of 3 is not an integer.
Is the square root of a 100 is a integer
No, the square root of 7 is NOT an Integer ...The square root of 7 = 2.64575131106
No, the square root of an integer will not always be an integer. It may or may not be. The square root of nine is three, both of which are integers. The square root of two is not an integer. In fact, it is not even a rational number.