3b+4 = b+12 3b-b = 12-4 2b = 8 b = 4
Let the numbers be represented by a and b with a < b. Then a = b.25/100 and b = a + 12 As a = b.25/100 then 100a = 25b : 4a = b As b = a + 12 then substituting for b gives, 4a = a + 12 : 3a = 12 : a = 4. If a = 4 then b = a + 12 = 4 + 12 = 16 The two numbers are 4 and 12.
The answer is 0
12 times 12 times 12 is equal to 1,728.
12 = -4/2 * -2 + b 12 = -2 * -2 + b 12 = 4 + b 8 = b
3b+4 = b+12 3b-b = 12-4 2b = 8 b = 4
It is: a/3 times b/4 = ab/12
3 times a times a times b
It is: 4(12+b) which is the same as 48+4b
A=b*h area = base (times) height P=2b + 2h perimeter = 2 (times) base (plus) 2 ( times) height A= b*h 12 = b*h 12/b = h let x = b h = 12/x since x = b and h = 12/x therefore P = 2x + 2(12/x)
Only if b is greater than 1 and less than 2 will 12b be greater than 12 and less than 24. If b is 1 or less, 12b will be less than or equal to 12 If b is 2 or more, 12b will be greater than or equal to 24.
12 and 60 ============ a + b = 72 a = 5b replacing a by 5b in the first equation 5b + b = 72 6b = 72 b = 12 72 - 12 = 60
4
10
12(12 - b) or -12(b - 12)
Let the numbers be represented by a and b with a < b. Then a = b.25/100 and b = a + 12 As a = b.25/100 then 100a = 25b : 4a = b As b = a + 12 then substituting for b gives, 4a = a + 12 : 3a = 12 : a = 4. If a = 4 then b = a + 12 = 4 + 12 = 16 The two numbers are 4 and 12.
b times b times b = b3 b plus b plus b = 3b