(3r - 2)(3r - 2) or (3r - 2) squared.
That factors to 3(r - 5)(r + 1) r = 5, -1
- 6r - 5 = 7 - 12r add 12r to both sides 12r - 6r - 5 = 7 - 12r + 12r 6r - 5 = 7 add 5 to both sides 6r - 5 + 5 = 7 + 5 6r = 12 divide both side integers by 6 r = 2 ---------- check in original equation -6(2) - 5 = 7 - 12(2) - 12 - 5 = 7 - 24 - 17 = - 17 checks
12r + 4 = 112, 12r = 108, r = 9
12r - 20
It is 12r - 20 or 4*(3r - 5)
(3r - 2)(3r - 2) or (3r - 2) squared.
That factors to 3(r - 5)(r + 1) r = 5, -1
To answer a quadratic like this, st everything equal to zero. 5r^2+12r=-4r^2-4 9r^2+12r+4=0 Ask yourself what two numbers add to get 12 that multiply to get 9*4=36 1*36 no 2*18 no 3*12 no 4*9 no 6*6 yes (3r+2)(3r+2) The first and last multiply to get 6 and the outside and inside multiply to get 6. That's (3r+)^2
-6r-5 = 7-12r 12r-6r = 7+5 6r = 12 r = 2
(3r + 18)/12 = (4r - 48)/4Multiply both sides by 12: (3r + 18) = 3*(4r - 48)or: 3r + 18 = 12r - 144Subtract 3r from both sides: 18 = 9r - 144Add 144 to both sides: 162 = 9rDivide both sides by 9: 18 = rAnswer: r = 18
5
- 6r - 5 = 7 - 12r add 12r to both sides 12r - 6r - 5 = 7 - 12r + 12r 6r - 5 = 7 add 5 to both sides 6r - 5 + 5 = 7 + 5 6r = 12 divide both side integers by 6 r = 2 ---------- check in original equation -6(2) - 5 = 7 - 12(2) - 12 - 5 = 7 - 24 - 17 = - 17 checks
If: -5 = 7+3r then the value of r works out as -4
-5 = 7 + 3r | subtract 7 -12 = 3r | divide by 3 -4 = r
(3r + 2)(r - 5)
3r - 5 in word is 'Three multiplied to 'r' and the whole then has '5' subtracted. '