g(x) = x/2
gf(5) = g(f(5)) = g(5+1) since f(x) = x+1 and then g(6) = 3*6 - 2 = 18 - 2 = 16
G(x) = log(2x) + 2, obviously!
g = f(x) = 3x + 2
g (x) = -3x+5 -3x= 5 x= -5/3
f(x)=x+1 g(f(x))=x f(x)-1=x g(x)=x-1
f and g are inverse functions.
g(x) = x + 3 Then f o g (x) = f(g(x)) = f(x + 3) = sqrt[(x+3) + 2] = sqrt(x + 5)
Yes
x
g(x) = 5. So whatever f(x) or f(-1) is, g of that is going to be 5.
Let f ( x ) = 3 x 5 and g ( x ) = 3 x 2 4 x
g(x) = x/2
x = 75
gf(5) = g(f(5)) = g(5+1) since f(x) = x+1 and then g(6) = 3*6 - 2 = 18 - 2 = 16
what is the domain of g(x) equals square root of x plus 1? √(x+1) ≥ 0 x+1≥0 x≥-1 Domain: [-1,∞)
G(x) = log(2x) + 2, obviously!