i is the constant for the imaginary unit.i ^2 = -1and therefore i = squareroot of -1
The x-intercepts of the function y = x2 + 3x + 2, can be determine by the quadratic equation which solves x2 + 3x + 2 = 0. In this case A = 1, B = 3, and C = 2. Compute x = (-B ± squareroot (B2 - 4AC)) ÷ 2A x = (-3 ± squareroot (9 - 4)) ÷ 2 x = -1.5 + squareroot (5) ÷ 2 and -1.5 - squareroot (5) ÷ 2 x ~= -0.382 and -2.618
((Squareroot)3/2 , 1/2)
Remember: squareroot of 3 is smaller than 2 and bigger than 1. It is approx. 1.732
4
Squareroot of 4 + Squareroot of 4 + Squareroot of 4 + 4=2+2+2+4=10
i is the constant for the imaginary unit.i ^2 = -1and therefore i = squareroot of -1
The x-intercepts of the function y = x2 + 3x + 2, can be determine by the quadratic equation which solves x2 + 3x + 2 = 0. In this case A = 1, B = 3, and C = 2. Compute x = (-B ± squareroot (B2 - 4AC)) ÷ 2A x = (-3 ± squareroot (9 - 4)) ÷ 2 x = -1.5 + squareroot (5) ÷ 2 and -1.5 - squareroot (5) ÷ 2 x ~= -0.382 and -2.618
((Squareroot)3/2 , 1/2)
the diagnol is the side of the square times squareroot(2) so the length of the side is 11/squareroot(2) and in simplified form your final answer is 11*squareroot(2)/2
This is the long way:x2 + 16 = 0x1= -1/2 + squareroot of -15,75x2 = -1/2 - sqareroot of - 15,75Note: squareroot of 16,25 is roughly ~ 4,03112575Well, so much for the theory, but this question does not have any solution, since you can't draw the squareroot of a negative number like - 15,75.And the short way:x2 + 16 = 0x2 = -16x = squareroot of - 16, which as I declared above, is not possible.Woops, I misunderstood your question; heres the answer to your question:f(x) = x2 + 16derivatef'(x) = 2xf'(0) = 2(0) Put in x = 0f'(0) = 0 When x = 0, the curve turns and you have a minimi point.f(0) = x2 + 16 Put in x = 0 in the first equation to get y.f(0) = 02 + 16f(0) = 16 y = 16minimum point: x = 0, y = 16 --> (0;16)
no if 1 plus 1 equals 2 then 2 plus 2 equals 4.
Remember: squareroot of 3 is smaller than 2 and bigger than 1. It is approx. 1.732
4
m7/2
x = -b+/-Squareroot b^2 - 4(a)(c) / 2(a)
1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 = 1 + 1 + 1 + 1 + 1 + 1 = 5