The square root of 1 = 1 ... (1 x 1 = 1)
1 - 1 + 2 = 2
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i is the constant for the imaginary unit.i ^2 = -1and therefore i = squareroot of -1
The x-intercepts of the function y = x2 + 3x + 2, can be determine by the quadratic equation which solves x2 + 3x + 2 = 0. In this case A = 1, B = 3, and C = 2. Compute x = (-B ± squareroot (B2 - 4AC)) ÷ 2A x = (-3 ± squareroot (9 - 4)) ÷ 2 x = -1.5 + squareroot (5) ÷ 2 and -1.5 - squareroot (5) ÷ 2 x ~= -0.382 and -2.618
((Squareroot)3/2 , 1/2)
Remember: squareroot of 3 is smaller than 2 and bigger than 1. It is approx. 1.732
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