X = 17.7 + 0.1y
2/y + 1 + 3 + 5y
2y^2+5y+2=(2y+1)(y+2)
The multiplicative inverse of 5y -xy + 1 is 1/5y -xy + 1 The additive inverse of 5y - xy + 1 is -5y + xy - 1
(4y - 1)(5y + 2)
(2, 1)
2/y + 1 + 3 + 5y
5y + 7 = 25y = -5y = -1
2y^2+5y+2=(2y+1)(y+2)
The multiplicative inverse of 5y -xy + 1 is 1/5y -xy + 1 The additive inverse of 5y - xy + 1 is -5y + xy - 1
(4y - 1)(5y + 2)
x + 5y = 10 5y = -x + 10 y = -x/5 + 2 m = -1/5 or .2
5y-2y= 3y+2 5y-2y-3y= 2 0y= 2
(2, 1)
(1, -1)
This is Simultaneous equ'ns. 3x + 5y = -1 2x -5y = 16 Add the two eq'ns. This will eliminate 'y' Hence 5x = 15 x = 3 When x = 3 , substitute into either eq'n to yimnd 'y'. Hence 3)3) + 5y = -1 9 + 5y = -1 5y = -10 y = -10/5 = -2 So the solution in ( x,y) form is ( 3, -2).
(-1, 2)
5y+8=7y subtract 5y from each side , 5y+8=7y -5y -5y 8=2y /2 /2 4=y