There are 998 of them: 2, 3, 4, 5, ... , 996, 997 998 and 999.
Since 2 plus 4 is not 10, the "if" statement is false. Given a false "if", logically, 9 + 2 can equal anything you like.
How about: 800+200 = 1000 or 2*500 = 1000
four
144, you add the plus numbers, then multiply it by the first.
500,500
Easier way than what?I presume you mean long multiplication of 999 by 999, adding 998 and adding 1.One way:999 = 1000 - 1 ⇒ 999 x 999 + 998 + 1 = (1000 - 1) x (1000 - 1) + 998 + 1= 10002 - 2 x 1000 + 1 + 998 + 1= 1000000 - 2 x 1000 + 1000= 1000000 - 1000= 999000Another way:998 + 1 = 999 ⇒ 999 x 999 + 998 + 1 = 999 x 999 + 999= 999 x (999 + 1)= 999 x 1000= 999000
1000 - 2 = 998
There are 998 of them: 2, 3, 4, 5, ... , 996, 997 998 and 999.
(1000-2)*180=998*180 You do the calculation.
The sum of the first 1,000 counting numbers (which excludes zero) is 500,001.
500,500
You use Plus as a symbol in Maths. Example, 2 Plus 2 equals 4. Or in symbols it would be 2+2=4. __________________________ Plus = + Equals = = (Equals equals =)
no if 1 plus 1 equals 2 then 2 plus 2 equals 4.
There is an equation to find the sum of a list of numbers . It is called the Arithmetic Progression. The equation is S(n) = (n/2)[a + (n-1)d] 4 Where n = number of terms (1000) a = first term (1000) d = difference between terms (1) Hence S(1000) = (1000/2)[1000 + ( 1000 - 1)(1)] S(1000) = 500[ 1000 + 999] S(1000) = 500[1999] S(1000) = 999500 The answer!!!!!
9998
No.