The expression (2c \times 2e) represents the multiplication of two terms. When multiplied, it results in (4ce), as you multiply the coefficients (2 and 2) together to get 4, and simply place the variables next to each other. Therefore, the final answer is (4ce).
4a*2c=8ac
8e4 / -4r3 = (2 x 4)e x e3 / -4r3 = -2e (e/r)3
12-2c = 2c add 2c to both sides 12 = 4c divide both sides by 4 3 = c
var(x) = E[(x - E(x))2] = E[(x - E(x)) (x - E(x))] <-------------Expand into brackets = E[x2 - xE(x) - xE(x) + (E(x))2] <---Simplify = E[x2 - 2xE(x) + (E(x))2] = E(x2) + E[-2xE(x)] + E[(E(x))2] = E(x2) - 2E[xE(x)] + E[(E(x))2] <---Bring (-2) constant outside = E(x2) - 2E(x)E[E(x)] + E[(E(x))2] <--- E[xE(x)] = E(x)E(x) = E(x2) - 2E(x)E(x) + [E(x)]2 <----------E[E(x)] = E(x) = E(x2) - 2[E(x)]2 + [E(x)]2 var(x) = E(x2) - [E(x)]2
2c=1p 2p=1q 4q=1g 4*8=x x=32
3ab x 2c = 6abc
2e+0 x 2e+0 x 2e+0 = 8e+0
4a*2c=8ac
32ce
2e-2 = 0.02. [X]e[Y] is the shorthand for scientific notation when formatting prevents you from using superscripts.
2c = 1 pint 312 pints x (2c/1pint) = 624c
3lnx - ln2=4 lnx^3 - ln2=4 ln(x^3/2)=4 (x^3)/2=e^4 x^3=2e^4 x=[2e^4]^(1/3)
a^2b^2c^2 ^2 is squared
2 x 10^-5 or 2E-5
It's impossible. Adding 5 odd numbers will always result in an odd number. 50 is an even number. Here's how. Let the five odd numbers be: 2a+1, 2b+1, 2c+1, 2d+1, and 2e+1; where a,b,c,d & e are any whole numbers. This guarantees that they are odd, since multiplying by 2 gets and even then an even plus one will be an odd. So we have 2a+1+2b+1+2c+1+2d+1+2e+1. Rearranging we have 2a+2b+2c+2d+2e+5 = 2(a+b+c+d+e) + 5. So 2(a+b+c+d+e) is even, then you add 5 and it's odd.
meant to be e^x = 2e^1-2x
the greatest common factor of 2c squared times 2c is 2c