4a*2c=8ac
12-2c = 2c add 2c to both sides 12 = 4c divide both sides by 4 3 = c
8e4 / -4r3 = (2 x 4)e x e3 / -4r3 = -2e (e/r)3
var(x) = E[(x - E(x))2] = E[(x - E(x)) (x - E(x))] <-------------Expand into brackets = E[x2 - xE(x) - xE(x) + (E(x))2] <---Simplify = E[x2 - 2xE(x) + (E(x))2] = E(x2) + E[-2xE(x)] + E[(E(x))2] = E(x2) - 2E[xE(x)] + E[(E(x))2] <---Bring (-2) constant outside = E(x2) - 2E(x)E[E(x)] + E[(E(x))2] <--- E[xE(x)] = E(x)E(x) = E(x2) - 2E(x)E(x) + [E(x)]2 <----------E[E(x)] = E(x) = E(x2) - 2[E(x)]2 + [E(x)]2 var(x) = E(x2) - [E(x)]2
2c=1p 2p=1q 4q=1g 4*8=x x=32
3ab x 2c = 6abc
2e+0 x 2e+0 x 2e+0 = 8e+0
4a*2c=8ac
32ce
2e-2 = 0.02. [X]e[Y] is the shorthand for scientific notation when formatting prevents you from using superscripts.
2c = 1 pint 312 pints x (2c/1pint) = 624c
3lnx - ln2=4 lnx^3 - ln2=4 ln(x^3/2)=4 (x^3)/2=e^4 x^3=2e^4 x=[2e^4]^(1/3)
a^2b^2c^2 ^2 is squared
2 x 10^-5 or 2E-5
It's impossible. Adding 5 odd numbers will always result in an odd number. 50 is an even number. Here's how. Let the five odd numbers be: 2a+1, 2b+1, 2c+1, 2d+1, and 2e+1; where a,b,c,d & e are any whole numbers. This guarantees that they are odd, since multiplying by 2 gets and even then an even plus one will be an odd. So we have 2a+1+2b+1+2c+1+2d+1+2e+1. Rearranging we have 2a+2b+2c+2d+2e+5 = 2(a+b+c+d+e) + 5. So 2(a+b+c+d+e) is even, then you add 5 and it's odd.
meant to be e^x = 2e^1-2x
the greatest common factor of 2c squared times 2c is 2c