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Q: What is a squared x b squared x c squared?

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x2

x squared + C.

âˆ« f(x)/[(f(x) + b)(f(x) + c)] dx = [b/(b - c)] âˆ« 1/(f(x) + b) dx - [c/(b - c)] âˆ« 1/(f(x) + c) dx b â‰ c

-17

a=64 b=8 (x+16x+64)=(x+8)^2

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ab x ac = ab - ac

he made the theorem C squared = A squared + B squared and A squared = C squared - B squared or B squared = C squared - A squared

well it could be anything, but I think you are thinking of Pythagoras' theorem. a(2) x b(2) = c(2) (2) = squared

If your Problem is organized like this: A x squared plus B x plus C, the equation is: (B plus or minus the square root of(B squared minus 4 A C)) over 2A

a^2+b^2=c^2a^2=c^2-b^2a=(c^2-b^2)^(1/2)

B squared equals c squared minus a squared then to find B take the square root of you answer for b squared

4

a(squared)+b(squared)=c(squared) The largest number is the c, and you can choose the a and b, since you need to find the a or the b. For example: You have the numbers 3, and 5 and you needed to find b. a(squared+b(squared)=c(squared) 3(squared)+b(squared)=5(squared) 9+b(squared)=25 -9 -9 b(squared)=16 Then take the square root b=4

it is asquared +b squared = c squared

if you mean a right triangle then the formula is a squared + b squared = c squared. a and b are the legs and c is the hypotunese. the legs are the smallest number then the hypotenese. An example is a=3 , b= ? and c =5 use the formula : a squared + b squared = c squared 3 squared + b squared = 5 squared 9 + b squared = 25 -9 - 9 _________________________________________ b squared = 16 Then you have to take the squared root of 16 which is 4 and 4 is b squared.

a squared + b squared = c squared a=leg b=leg c=hypotenuse

c= sq rt of 73

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