a^2b^2c^2
^2 is squared
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x squared + C.
-17
∫ f(x)/[(f(x) + b)(f(x) + c)] dx = [b/(b - c)] ∫ 1/(f(x) + b) dx - [c/(b - c)] ∫ 1/(f(x) + c) dx b ≠c
a=64 b=8 (x+16x+64)=(x+8)^2
Use the quadratic formula, with a = 1, b = -3, c = 2.