x squared + C.
-17
∫ f(x)/[(f(x) + b)(f(x) + c)] dx = [b/(b - c)] ∫ 1/(f(x) + b) dx - [c/(b - c)] ∫ 1/(f(x) + c) dx b ≠c
a=64 b=8 (x+16x+64)=(x+8)^2
Use the quadratic formula, with a = 1, b = -3, c = 2.
ab x ac = ab - ac
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
he made the theorem C squared = A squared + B squared and A squared = C squared - B squared or B squared = C squared - A squared
well it could be anything, but I think you are thinking of Pythagoras' theorem. a(2) x b(2) = c(2) (2) = squared
If your Problem is organized like this: A x squared plus B x plus C, the equation is: (B plus or minus the square root of(B squared minus 4 A C)) over 2A
B squared equals c squared minus a squared then to find B take the square root of you answer for b squared
a(squared)+b(squared)=c(squared) The largest number is the c, and you can choose the a and b, since you need to find the a or the b. For example: You have the numbers 3, and 5 and you needed to find b. a(squared+b(squared)=c(squared) 3(squared)+b(squared)=5(squared) 9+b(squared)=25 -9 -9 b(squared)=16 Then take the square root b=4
if you mean a right triangle then the formula is a squared + b squared = c squared. a and b are the legs and c is the hypotunese. the legs are the smallest number then the hypotenese. An example is a=3 , b= ? and c =5 use the formula : a squared + b squared = c squared 3 squared + b squared = 5 squared 9 + b squared = 25 -9 - 9 _________________________________________ b squared = 16 Then you have to take the squared root of 16 which is 4 and 4 is b squared.
4
it is asquared +b squared = c squared
a squared + b squared = c squared a=leg b=leg c=hypotenuse
You add c squared and b squared together to get a squared. This is based on the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (a) is equal to the sum of the squares of the other two sides (b and c).