2x2-2 = -5x-1 2x2+5x-2+1 = 0 2x2+5x-1 = 0 Use the quadratic equation formula to find the values of x: x = 0.1861406616 or x = -2.686140662
2x2 + (5x-4x)2 + (x-x)2 = 2x2 + x2 + 02 = 2x2 + x2 = 3x2
2X2+5x-12 4+5x-12 -8+5x 5x-8
2x2 + 5x - 3 (2x - 1)(x + 3)
2x2+5x-3 = 0 (2x-1)(x+3) = 0 x = 1/2 or x -3
2x2-2 = -5x-1 2x2+5x-2+1 = 0 2x2+5x-1 = 0 Use the quadratic equation formula to find the values of x: x = 0.1861406616 or x = -2.686140662
2x2 + (5x-4x)2 + (x-x)2 = 2x2 + x2 + 02 = 2x2 + x2 = 3x2
2X2+5x-12 4+5x-12 -8+5x 5x-8
2x2 - 5x + 12 does not factor. 2x2 - 5x - 12 factors into (2x + 3)(x - 4) 2x2 + 5x - 12 factors into (2x - 3)(x + 4)
(x - 2)(2x + 9)
2x2 + 5x - 3 (2x - 1)(x + 3)
You would first factor out anything that is common between the 3 parts. 2x2 is the greatest common factor. To pull out the 2x2, you divide each term by 2x2 like so:12x4/2x2=6x210x3/2x2=5x-12x2/2x2=-6We now know that 12x4+10x3-12x2= 2x2(6x2+5x-6)The next step involves using the "slip and slide" method for the trinomial inside the parentheses:6x2+5x-6x2+5x-36(x+9)(x-4)(x+9/6)(x-4/6)(x+3/2)(x-2/3)(2x+3)(3x-2)Remembering that the result for the slip and slide method only accounts for 6x2+5x-6 we must multiply (2x+3)(3x-2) by 2x2.Your final answer is 2x2(2x+3)(3x-2).
2x2+5x-3 = 0 (2x-1)(x+3) = 0 x = 1/2 or x -3
x3 + 2x2 + 5x + 4 = (x + 1)(x2 + x + 4)
Provided that x- 2 is not zero: 2x3 + x2 - 13x + 6 = 2x3 - 4x2 + 5x2 - 10x - 3x + 6 = 2x2*(x - 2) + 5x*(x - 2) - 3*(x - 2) = (x - 2)*(2x2 + 5x - 3) Therefore, (2x3 + x2 - 13x + 6)/(x - 2) = (x - 2)*(2x2 + 5x - 3)/(x - 2) = 2x2 + 5x - 3 If x = 2 so that x - 2 = 0, then the expression is not defined.
I messed up the question I ment what are the solutions to 2x^2 + 5x + 8 = 6
2x2 - 5x + 6 = ?x = -1(2 x (-1)2) - (5 x -1) + 6 = ?(2 x 1) - (-5) + 6 = ?2 + 5 + 6 = 13