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Q: What is 2xy 20 if x is 2 and y is 5?

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2xy=2*30*2=120

2xy x is 2 y is 7 therefore (2)(2)(7) = 28

The question doesn't nail it down; i.e., there can be several answers that satisfy the given information. Perimeter 'P' = 2 x (Length + Width) Area 'A' = (Length) x (Width) = 2 x y What is the Length, and what is the Width ? Here are five correct answers: ==> If the rectangle is (2) by (x y), A = 2xy, P = 4 + 2xy ==> If the rectangle is (2x) by (y), A = 2xy, P = 4x + 2y ==> If the rectangle is (x) by (2y), A = 2xy, P = 2x + 4y ==> If the rectangle is (1) by (2xy), A = 2xy, P = 2 + 4xy ==> If the rectangle is (0.1) by (20xy), A = 2xy, P = 0.2 + 40xy

2xy*9 if x=3 and y = 2 2(3)(2)*9 12*9 108 You substitute x and y for their equivalent (3 and 2) then simply multiply 2*x*y, then multiply the answer of that by 9.

2xy

Related questions

2xy substitute 3 for y and 5 for x 2(5)(3) = 30

(x^2 + 2y)(x^3 - 2xy + y^3) = x^2(x^3 - 2xy + y^3) + 2y(x^3 - 2xy + y^3) Now, let's distribute each term: = x^2 * x^3 - x^2 * 2xy + x^2 * y^3 + 2y * x^3 - 2y * 2xy + 2y * y^3 Now, simplify each term: = x^5 - 2x^3y + x^2y^3 + 2x^3y - 4xy^2 + 2y^4 Now, combine like terms: = x^5 + x^2y^3 - 4xy^2 + 2y^4 So, the expanded form of (x^2 + 2y)(x^3 - 2xy + y^3) is x^5 + x^2y^3 - 4xy^2 + 2y^4.

(2xy)x=2x2y

2xy=2*30*2=120

(x-y)2 is a square so (x-y)2 >= 0 expanding, x2 - 2xy + y2 >= 0 so x2 + y2 >= 2xy or 2xy <= x2 + y2

2xy x is 2 y is 7 therefore (2)(2)(7) = 28

(2xy-4x)+ (8y-16)=2xy-4x+8y-16, which factors as 2(x+4)(y-2)

(x + 4y)(x - 6y)

The question doesn't nail it down; i.e., there can be several answers that satisfy the given information. Perimeter 'P' = 2 x (Length + Width) Area 'A' = (Length) x (Width) = 2 x y What is the Length, and what is the Width ? Here are five correct answers: ==> If the rectangle is (2) by (x y), A = 2xy, P = 4 + 2xy ==> If the rectangle is (2x) by (y), A = 2xy, P = 4x + 2y ==> If the rectangle is (x) by (2y), A = 2xy, P = 2x + 4y ==> If the rectangle is (1) by (2xy), A = 2xy, P = 2 + 4xy ==> If the rectangle is (0.1) by (20xy), A = 2xy, P = 0.2 + 40xy

2xy*9 if x=3 and y = 2 2(3)(2)*9 12*9 108 You substitute x and y for their equivalent (3 and 2) then simply multiply 2*x*y, then multiply the answer of that by 9.

2xy

The prime factorization of 20 = 2 x 2 x 5 or 2^2 x 5 2 x 2 x 5 = 20