2y4(16 - x4) = 2y4 (4 + x2)(4 - x2) = 2y4(4 + x2)(2 + x)(2 - x)
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
To do this equation, there would have to be an = in it. If you mean 5x-2y=4, then: 5x-2y=4 -5x -5x = -2y=4-5x Hope this helped!
If you mean: 16x-2y = 4 then y = 8x-2, and its slope is 8 with a y intercept of -2; any line parallel to it will have a slope of 8 but with a different y intercept.
(6/6)+(6/6)+(6/6)+6=9
2y4(16 - x4) = 2y4 (4 + x2)(4 - x2) = 2y4(4 + x2)(2 + x)(2 - x)
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
graph the inequality 5x+2y<4
Set it equal to 0 and subtract x and solve for y
Assuming the line is 3x - 2y = 4, the point (1, -1/2) lies in it.
If you mean: 4x -3y = 1 and x -2y = 4 then the solutions are x = -2 and y = -3
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To do this equation, there would have to be an = in it. If you mean 5x-2y=4, then: 5x-2y=4 -5x -5x = -2y=4-5x Hope this helped!
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If you mean: 16x-2y = 4 then y = 8x-2, and its slope is 8 with a y intercept of -2; any line parallel to it will have a slope of 8 but with a different y intercept.
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