If: 12k = 84 then k = 7
n=1 a(1) = 0.001 n=2 a(2) = 0.012 n=3 a(3) = 0.144 n=4 a(4) = 1.728 n=5 a(5) = 20.736 .... n=k a(k) = (12^(k-1))/1000 let n = k+1 a(k+1) = 12^(k)/1000 12(ak) = a(k+1) 12(12^k-1)/1000 = 12^k/1000 the 12 gets absorbed here. 12^(k-1+1)/1000 = 12^k/1000 Valid for k and k+1 therefore our equation A(n) = 12^(n-1)/1000, n(greater than or equal to) 1
The equation is xy = k where k is the constant of variation. It can also be expressed y = k over x where k is the constant of variation.
In the equation m = k + 3, m is the:
12, 24, 36, 48, 60, 72, 84, 96, 108, 120, 132 and 144 are just a few (note the Least Common Multiple is 12, and any multipleof 12 will be a common multiple of 4 and 6)
if x varies inversely as y then xy is a constant (k) eg if x doubles as y halves then examples are: x = 6, y = any then k = 6y when x = 12, y = any/2 then k = 12/2 times any ie 6y.
Any number of the form 84*k, where k is an integer, is evenly divisible.
They are members of the infinite set of numbers of the form 84*k where k is any integer.
79 + k = 84 84 - 79 = k k = 5
To graph the equation ( y = k ) (where ( k ) is a constant) on a TI-84 calculator, first press the "Y=" button to access the function editor. Then, enter the value of ( k ) in one of the function lines (e.g., ( Y_1 = k )). After that, press the "GRAPH" button to display the horizontal line representing the equation on the graphing screen. Adjust the window settings if necessary to ensure the line is visible.
They are members of the infinite set of numbers of the form 84*k where k is an integer. Since the set is infinite, it is not possible to list them.
A line in the X-Y plane follows an equation y = (slope X x) plus a constant k. In this instances, 5 = [(-12)(3)] + k, or k = 5 + 36 = 41. Therefore, the equation is: y = -12x + 41.
k2 + 3k =108k2 + 3k - 108 = 0(k - 9) (k + 12)k = -9 , k = 12ANSWER:k = -9 , k = 12I hope this helps!
If y and x are related inversely, then the equation for y can be said to be:y = k/xTo find the constant k, substitute 12 for y and 6 for x (a pair of values that are known to satisfy the equation).y = k/x12 = k/612 X 6 = k72 = kThe value of the variation constant k is 72.
It is any fraction of the form (21*k)/(84*k) where k is a non-zero integer, or a common factor of the two.
a sign is missing, but if 11k - 13 = 119 then 11k = 132 and k = 12.
n=1 a(1) = 0.001 n=2 a(2) = 0.012 n=3 a(3) = 0.144 n=4 a(4) = 1.728 n=5 a(5) = 20.736 .... n=k a(k) = (12^(k-1))/1000 let n = k+1 a(k+1) = 12^(k)/1000 12(ak) = a(k+1) 12(12^k-1)/1000 = 12^k/1000 the 12 gets absorbed here. 12^(k-1+1)/1000 = 12^k/1000 Valid for k and k+1 therefore our equation A(n) = 12^(n-1)/1000, n(greater than or equal to) 1
The equation is xy = k where k is the constant of variation. It can also be expressed y = k over x where k is the constant of variation.