The width is 3 m because 4+3+4+3 = 14 m
3/4 of 2 m = 6/4 = 1.5 metres.3/4 of 2 m = 6/4 = 1.5 metres.3/4 of 2 m = 6/4 = 1.5 metres.3/4 of 2 m = 6/4 = 1.5 metres.
It is: 4 times 3.2 = 12.8 square m
m=y2-y1/x2-x1 m=3-0/0-4 m=3/-4 m=-3/4 if the points you mean are (4,0) and (0,3)
Answer: 'm' times. Examples: If m=2, Then m2 = (2x2) = 4 -> 4-2-2 = 0 (So subtracted TWICE) If m=4 Then m2 = (4x4) = 16 -> 16-4-4-4-4 = 0 (So subtracted FOUR TIMES) This works no matter how large the number is!
7m
( m^2 - m - 3 ) + ( m - 4 ) = m^2 - m - 3 + m - 4 = m^2 - 7Answer: m^2 - 7
Three times the difference of a and m divided by twice their sum is equal to 6(a squared - m squared). 3(a - m)/2(a + m)
m^4 x m^3 = m^7Using a numerical example, 2^4 x 2^3 = 16 x 8 = 128 = 2^7
The math problem M time 3 times 4 times 6 subtract 6 equals 432. In order for you to find this answer is doing a little math.
the sum of 3 times m and n
The width is 3 m because 4+3+4+3 = 14 m
105. 3/4 x 140 so 140 divided by 4 which is 35 times it by 3.
3 and 3/4 around a 400 m track
Let the two integers be m-1 & m, so the lesser integer is m-1, and the greater integer is m:(m-1) + 3*m = 43 --> 4*m -1 = 43 --> 4*m = 44, m = 11 & m-1 = 10, so 10 & 11Check: 11 times 3 is 33, add 10 is 43
5/6 - m/4 = 1/3. First isolate the variable m, start by adding m/4 to both sides. 5/6 = 1/3 + m/4. Then subtract 1/3 from each side. 5/6 - 1/3 = m/4. Next multiply both sides by 4. 4 ( 5/6 - 1/3 ) = m. Then solve for m. 4 ( 5/6 - 2/6 ) = m. 4 ( 3/6 ) = m 4 ( 1/2 ) = m 2 = m
3/4 of 2 m = 6/4 = 1.5 metres.3/4 of 2 m = 6/4 = 1.5 metres.3/4 of 2 m = 6/4 = 1.5 metres.3/4 of 2 m = 6/4 = 1.5 metres.