the sum of 3 times m and n
Three times the difference of a and m divided by twice their sum is equal to 6(a squared - m squared). 3(a - m)/2(a + m)
sum = 2n + 3m
( m^2 - m - 3 ) + ( m - 4 ) = m^2 - m - 3 + m - 4 = m^2 - 7Answer: m^2 - 7
x + 3x = 52 4x = 52 x = 13 Mrs. Computer is 39 and Mousy is 13. To solve this problem I gave each of the people a representative letter. Mrs Computer = C and Mousy = M The first statment "Mrs Computer is 3 times older that her daughter Mousy" translates to this C=M*3 The second statement "the sum of their ages is 52" translates to this M+C=52 Because we know that C=M*3 I can translate "How old is Mousy" to this equation M+3*M=52 which simplifies to this 4*M=52 then further to this M=52/4
It is quite easy to prove this using algebra. Suppose x is the smaller of the two odd integer. The fact that x is odd means that it is of the form 2m + 1 where m is an integer. [m integer => 2m is an even integer => 2m + 1 is odd] The next odd integer will be x + 2, which is (2m + 1) + 2 = 2m + 3 The sum of these two consecutive odd integers is, therefore, 2m + 1 + 2m + 3 = 4m + 4 = 4(m + 1) Since m is an integer, m+1 is an integer and so 4(m + 1) represents a factorisation of the answer which implies that 4 is a factor of the sum. In other words, the sum is a multiple of 4.
4*m/5 + 18
Ya mums fat cow
m^4 x m^3 = m^7Using a numerical example, 2^4 x 2^3 = 16 x 8 = 128 = 2^7
3.582km or 3582 m
Yes. A multiple of 4 can be written as 4j, where j is any integer. So for example, letting j = 1, 2, 3, 4, 5, etc., leads to values for 4j of 4, 8, 12, 16, 20, etc; all being multiples of 4. So if we have two multiples of 4, say 4m and 4n (with m and n both being integers), then their sum will be 4m + 4n, which can also be written as 4(m + n) by factoring out the 4. Since m and n are integers, (m + n) will also be an integer, so the sum of 4(m + n) is a multiple of 4.
The math problem M time 3 times 4 times 6 subtract 6 equals 432. In order for you to find this answer is doing a little math.