Answer: no solution
3x - 2 = 3x -5
3x - 3x - 2 = 3x - 3x - 5 (Subtract 3x from each side.)
-2 = -5 Huh??
When you are solving an equation, and the variable disappears, there are two possibilities:
If you are left with a true statement (such as 2 = 2), then the equation is an identity, and any value of x will satisfy the equation. The number of solutions is infinite.
If you are left with a false statement, as in this case, no value of x will satisfy the equation. There is no solution.
x=-.25.
3x2 = 21 describes two single values, and does not have an x intercept. 3x2 = 21 ∴ x2 = 7 ∴ x = ±√7
3x2-9x = 0 x(3x-9) = 0 x = 0 or x = 3
3x2 + 2x = 16 ∴ 3x2 + 2x - 16 = 0 ∴ 3x2 - 6x + 8x - 16 = 0 ∴ 3x(x - 2) + 8(x - 2) = 0 ∴ (3x + 8)(x - 2) = 0 ∴ x ∈ {-8/3, 2}
3x2 + x - 2 = 0(3x - 2) (x + 1) = 0x = + 2/3x = -1
x=-.25.
Set the equation equal to zero. 3x2 - x = -1 3x2 - x + 1 = 0 The equation is quadratic, but can not be factored. Use the quadratic equation.
3x2 = 21 describes two single values, and does not have an x intercept. 3x2 = 21 ∴ x2 = 7 ∴ x = ±√7
-3x2 + 22x = 0 You start by dividing both sides by x: ∴ -3x + 22 = 0 Then rearrange to solve for x: ∴3x = 22 ∴ x = 7 + 1/3
If you mean 3x2-7x+x = -4 then there are no solutions because the discriminant of the quadratic equation is less than zero.
3x2+x-4 = 0 (3x+4)(x-1) = 0 Solutions: x = 1 and x = -4/3 By using the quadratic equation formula.
3x2-9x = 0 x(3x-9) = 0 x = 0 or x = 3
3x2 + 2x = 16 ∴ 3x2 + 2x - 16 = 0 ∴ 3x2 - 6x + 8x - 16 = 0 ∴ 3x(x - 2) + 8(x - 2) = 0 ∴ (3x + 8)(x - 2) = 0 ∴ x ∈ {-8/3, 2}
3x2 + x - 2 = 0(3x - 2) (x + 1) = 0x = + 2/3x = -1
95
3 x 7 = 3 x (5 + 2) And since multiplication is distributive over addition, 3 x (5 + 2) = 3 x 5 + 3 x 2
3x2 when x = 2 is the answer 3 X 4 = 12 or is the answer (3 X 2)2 = 62 = 36