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2x-6x plus 3x equals -41?
2x - 6x + 3x = -412x - 3x = -41-1x = -41x = 41
What is the 3 consecutive integers added to get 41?
44
3x plus 4x plus 6 equals 41?
x=5
What is the answerThe sum of triple a number and 5 is 41?
Let the number be x and so if 3x+5 = 41 then x = 12
If the Lines AB and CD are perpendicular to each other. If 1 measures (3x plus 4) and deg and 2 measures 41 and deg what is the value of x?
If lines AB and CD are perpendicular, the sum of their angles must equal 90 degrees. Given that one angle measures (3x + 4) degrees and the other measures 41 degrees, we can set up the equation: [ (3x + 4) + 41 = 90 ] Simplifying this gives (3x + 45 = 90). Subtracting 45 from both sides results in (3x = 45), leading to (x = 15).
2x-6x plus 3x equals -41?
2x - 6x + 3x = -412x - 3x = -41-1x = -41x = 41
What is 3x-x44?
3x-x44 = -41
What is the 3 consecutive integers added to get 41?
44
If 2x 3y 17 and 3x 4y 24 then 5x 7y?
41
3x plus 4x plus 6 equals 41?
x=5
If g(x) 3x plus 1 evaluate g(-14).?
It is -41.
What is the answerThe sum of triple a number and 5 is 41?
Let the number be x and so if 3x+5 = 41 then x = 12
What is the value of c if the discriminant of negative 2x squared minus 3x plus c is 41 and what is the standard form of the expression i over 2 plus i?
Presumably you mean: -2x2-3x+41 If so then the discriminant is: (-3)2-4*-2*41 = 337 The expession is: i/2+i
If the Lines AB and CD are perpendicular to each other. If 1 measures (3x plus 4) and deg and 2 measures 41 and deg what is the value of x?
If lines AB and CD are perpendicular, the sum of their angles must equal 90 degrees. Given that one angle measures (3x + 4) degrees and the other measures 41 degrees, we can set up the equation: [ (3x + 4) + 41 = 90 ] Simplifying this gives (3x + 45 = 90). Subtracting 45 from both sides results in (3x = 45), leading to (x = 15).
What is 5x plus 17 equals 2x plus 41?
3x = 24, x = 8
What are two expressions where the solutions is 41?
Two expressions where the solution equals 41 are ( x + 7 = 48 ) and ( 3x - 2 = 121 ). In the first expression, solving for ( x ) gives ( x = 41 ). In the second expression, solving for ( x ) also yields ( x = 41 ).
How do you solve 3x-28-5x equals 5x plus 13?
3x-28-5x=5x+13 Let us first solve the variables -2x-28=5x+13 Transposing -28 to Right hand side -2x=5x+13+28 -2x=5x+41 Transposing 5x to left hand side -2x-5x=41 -7x=41 equation 1 x=41/-7 x=-41/7 Hence the required answer is -41/7. You can verify it by substituting the value of x in the given equation. If Right hand side is equal to Left hand side the answer is right. Let us verify Substituting the value of x=-41/7 in the given equation1 -7(-41/7)=41 -7 X -41/7 =41 41=41 LHS=RHS Hence Verified
