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2x-6x plus 3x equals -41?
2x - 6x + 3x = -412x - 3x = -41-1x = -41x = 41
What is the 3 consecutive integers added to get 41?
44
3x plus 4x plus 6 equals 41?
x=5
What is the answerThe sum of triple a number and 5 is 41?
Let the number be x and so if 3x+5 = 41 then x = 12
What is 5x plus 17 equals 2x plus 41?
3x = 24, x = 8
2x-6x plus 3x equals -41?
2x - 6x + 3x = -412x - 3x = -41-1x = -41x = 41
What is 3x-x44?
3x-x44 = -41
What is the 3 consecutive integers added to get 41?
44
If 2x 3y 17 and 3x 4y 24 then 5x 7y?
41
3x plus 4x plus 6 equals 41?
x=5
If g(x) 3x plus 1 evaluate g(-14).?
It is -41.
What is the answerThe sum of triple a number and 5 is 41?
Let the number be x and so if 3x+5 = 41 then x = 12
What is the value of c if the discriminant of negative 2x squared minus 3x plus c is 41 and what is the standard form of the expression i over 2 plus i?
Presumably you mean: -2x2-3x+41 If so then the discriminant is: (-3)2-4*-2*41 = 337 The expession is: i/2+i
What is 5x plus 17 equals 2x plus 41?
3x = 24, x = 8
What are two expressions where the solutions is 41?
Two expressions where the solution equals 41 are ( x + 7 = 48 ) and ( 3x - 2 = 121 ). In the first expression, solving for ( x ) gives ( x = 41 ). In the second expression, solving for ( x ) also yields ( x = 41 ).
How do you solve 3x-28-5x equals 5x plus 13?
3x-28-5x=5x+13 Let us first solve the variables -2x-28=5x+13 Transposing -28 to Right hand side -2x=5x+13+28 -2x=5x+41 Transposing 5x to left hand side -2x-5x=41 -7x=41 equation 1 x=41/-7 x=-41/7 Hence the required answer is -41/7. You can verify it by substituting the value of x in the given equation. If Right hand side is equal to Left hand side the answer is right. Let us verify Substituting the value of x=-41/7 in the given equation1 -7(-41/7)=41 -7 X -41/7 =41 41=41 LHS=RHS Hence Verified
What three consecutive numbers added together equal 120?
The consecutive integers are 39, 40, and 41. To solve this algebraically, note that consecutive numbers can be indicated by the variables x, x+1, and x+2. For the sum x + (x+1) + (x+2) = 120, 3x +3 = 120 3x= 117 x= 39, followed by 40 and 41 39+40+41 = 120
