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Veda Glover

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3y ago
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13y ago

(x) + (x+1) + (x+2) = 41

3x + 3= 41

3x = 38

x = 12.666666666...

no 3 consecutive integers add up to 41

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Q: What is the 3 consecutive integers added to get 41?
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Three consecutive odd integers that have a sum of 123?

123/3 = 41 so integers are 39, 41 and 43


Find 3 consecutive integers whose sum is 126?

The integers are are 41, 42 and 43.


What are 3 consecutive integers whose sum is 126?

41+42+43=126.


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There is no set of three consecutive integers for 106.


What three consecutive numbers added together equal 120?

The consecutive integers are 39, 40, and 41. To solve this algebraically, note that consecutive numbers can be indicated by the variables x, x+1, and x+2. For the sum x + (x+1) + (x+2) = 120, 3x +3 = 120 3x= 117 x= 39, followed by 40 and 41 39+40+41 = 120


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123/3 - 2, 123/3 and 123/3 + 2 ie 39, 41 and 43.


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Find three consecutive integers whose sum is 126?

Let the intgers be n- 1 n , & n+1 . This is consecutive. Hence Adding (n-1) + n + ( n +1) = 126 Add the LHS 3n = 126 Divide both sides by '3' n = 42 Hence n- 1 = 41 & n +1 = 43 So the consecutive integers are 41,42, & 43.


The sum of three consecutive odd integers is -3 what are the integers?

Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.


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Find three Consecutive odd integers whose sum is 117?

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