44
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(x) + (x+1) + (x+2) = 41
3x + 3= 41
3x = 38
x = 12.666666666...
no 3 consecutive integers add up to 41
123/3 = 41 so integers are 39, 41 and 43
The integers are are 41, 42 and 43.
There is no set of three consecutive integers for 106.
The consecutive integers are 39, 40, and 41. To solve this algebraically, note that consecutive numbers can be indicated by the variables x, x+1, and x+2. For the sum x + (x+1) + (x+2) = 120, 3x +3 = 120 3x= 117 x= 39, followed by 40 and 41 39+40+41 = 120
123/3 - 2, 123/3 and 123/3 + 2 ie 39, 41 and 43.