12ab+3ab=15ab
4a3 - 4a2 = 4a2*(a - 1)
GCF(6a2bx, 15ab2x-24ab) = GCF[6a2bx, 3ab(5bx-8)] = 3ab
If a is an integer then 4 divides 4a2 so it cannot be a prime. If a = 0 then 4a2 = 0 and cannot be simplified further If a = 1 then 4a2 = 4 = 2*2 If a is an integer > 1, then 4a2 = 2*2*a*a If a is not an integer, then there are too many possible options for the answer.
3ab
4a2
2a-3ab = -1
Assuming multiplication, it's 4a2.
3ab x 2c = 6abc
12ab+3ab=15ab
4a2+ 25 does not factor over the real number field. In the complex numbers , it factors as (2a +5i)(2a - 5i). This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2
4a3 - 4a2 = 4a2*(a - 1)
GCF(6a2bx, 15ab2x-24ab) = GCF[6a2bx, 3ab(5bx-8)] = 3ab
If a is an integer then 4 divides 4a2 so it cannot be a prime. If a = 0 then 4a2 = 0 and cannot be simplified further If a = 1 then 4a2 = 4 = 2*2 If a is an integer > 1, then 4a2 = 2*2*a*a If a is not an integer, then there are too many possible options for the answer.
3ab - a - 3b2 + b = -3b2 + 3ab + b - a = -3b(b - a) + 1(b - a) = (1 - 3b)(b - a)
4a2
4a2 - 20ab2 + 25b4 (2a - 5b2)(2a - 5b2) (2a - 5b2)2