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4a2 - 9a + 5 = 4a2 - 4a -5a + 5 = 4a(a - 1) - 5(a - 1) = (4a - 5)(a - 1)
√(4a + 4) = √4(a + 1) = 2√(a + 1).
4a3 - 4a2 = 4a2*(a - 1)
4a + 1 - a =19, rewrite your question, 4a + -a + 1 =19, 3a + 1 =19, subtract 1 from each side 3a = 18, divide by 3, a =6
if you write (type) it out... 4a-1=15 add 1 to both sides 4a=16 divide both sides by 4 a=4