1. 4x + 3y = -2
2. x - y = -4
Multiplying 2. by 3 gives: (we have done this so that we end up with a -3y)
3. 3x - 3y = -12
1. added to 3. gives: (now, by adding, the 3y & -3y will cancel out)
4. 7x = -14 (the 4x + the 3x gives 7x, the y's cancel out, -2 + -12 gives -14)
thus x = -14/7
x = -2
Substituting x = -2 into 1. gives
(4 * -2) + 3y = -2
-8 + 3y = -2
3y = -2 + 8
3y = 6
y = 2
Thus x = -2 and y = 2.
4xy+1=3y-7x 4xy-3y=-7x-1 y(4x-3)=-7x-1 y=(-7x-1)/(4x-3)
xy(3x - 2y)(2x + 3y)
mid point of xy
y(z+x) + 4(x+z)
y = x/(x - 3) so y(x - 3) = x xy - 3y = x xy - x = 3y x(y - 1) = 3y x = 3y/(y - 1) for y ≠1 So, the inverse function is f(y) = 3y/(y - 1) where y ≠1
4xy+1=3y-7x 4xy-3y=-7x-1 y(4x-3)=-7x-1 y=(-7x-1)/(4x-3)
x + y = 154x + 3y = 38from the first equation, y = 15-xsubstitute this value in the second equation as follows:4x + 3(15-x)= 384x + 45 - 3x = 38x + 45 = 38x = 38 - 45so, x = -7substitute this value to solve for y:y = 15 -xy = 15-(-7)y = 22
That equals 2xy + 3y which factors to y(2x + 3)
3Y - 12X = 0add 12X to both sides3Y = 12Xdivide both sides integers by 3(3/3)Y = (12/3)XY = 4X---------------the function
Divide by 'x'; x2+xy/x = x(x+y)
4x-y2=2xy 2x ? y5 if its plus its 7 xy
If you mean, "x-3y = 12", then xy = 3y2 + 12y.
-1
xy(3x - 2y)(2x + 3y)
mid point of xy
In order to combine terms, the variable(s) must be the same and the exponent(s) must be the same on the variables. Since you have an x2 term, x term, xy term and y term, none of the terms can be combined. So, the answer is: x2 + 4x + xy + 4y. The only thing you could do in this problem is to factor out a 4 from the 4x & 4y so another way to write this is: x2 + xy + 4(x + y).
y(z+x) + 4(x+z)