3x+2y=20 5x-2y=1 (3x+2y) + (5x-2y)= 20+1 3x+5x= 21....... 8x=21.........x=2 5/8 Subsitute x=3(2 5/8)+ 2y=20........... 7 7/8 +2y=20.........2y= 20- 7 7/8....... y=6 1/16
If as a straight line equation: 5x+2y = 20 then y = -2.5x+10 whereas -2.5 is the slope and 10 is the y intercept
5x 2y = 10
5x-2y=-3 -2y=-5x-3 y=(5/2)x+3/2 slope is 5/2
5x - 2y = 10 2y = 5x - 10 y = 2.5x - 5......which is the equation in slope intercept form.
3x+2y=20 5x-2y=1 (3x+2y) + (5x-2y)= 20+1 3x+5x= 21....... 8x=21.........x=2 5/8 Subsitute x=3(2 5/8)+ 2y=20........... 7 7/8 +2y=20.........2y= 20- 7 7/8....... y=6 1/16
If as a straight line equation: 5x+2y = 20 then y = -2.5x+10 whereas -2.5 is the slope and 10 is the y intercept
write equation in standfrd form y =mx + b where b = y intercept 5x - 2y =20 5x -20 = 2y 5/2 x -10 = y when x = 0 y = -10, the y intercept
5X - 2Y = 20 -2Y = -5X + 20 Y = 5/2X - 10 set to 0 and solve for X 5/2X - 10 = 0 5/2X = 10 X = 4 My TI-84 graphs and confirms this
Assuming you meant 5x-2y=20... 5x - 2(0) = 20 5x = 20 x = 4 X-intercept is 4
5x 2y = 10
5x - 2y = 20The x-intercept of a line is the point where its y-value is 0. When y=0, we get 5x = 20, or x=4. This means the coordinates of the x-intercept on this line are (4,0).
(3, 2)
5x-2y=11 -2y=-5x+11 y=(5/2)x - 11/2 Slope is 5/2
5x-2y=-3 -2y=-5x-3 y=(5/2)x+3/2 slope is 5/2
5x - 2y = 10 2y = 5x - 10 y = 2.5x - 5......which is the equation in slope intercept form.
The x intercept is the point where y = 0, the y intercept is the point where x =0: For the x intercept: 5x + 2y = 20, but y = 0 => 5x + 0 = 20 => x = 20/5 = 4. So the x intercept is at (4, 0). For the y intercept: 5x + 2y = 20, but x = 0 [The rest of the calculation is left as an exercise for the reader.]