a(a^2 + 1)
(x - 1)(x - 1)(x - 1) - (x + 1)(x + 1)(x + 1)
(X + 1)3 = X3 + 3X2 + 3X + 1
(x - 1)(2x^2-1)
The answer is (2x^2+3)(4x+1)
No.
140x / 64y divide 5x/8y = > 40x/64y X 8y/5x Note the change of sign and the inversion of the Right hand fraction. Cancel down by '5x' 8/64y X 8y/1 Cancel down by '8y' 8/8 X 1/1 = 8/8 = 1 The answer!!!!
a(a^2 + 1)
sin cubed + cos cubed (sin + cos)( sin squared - sin.cos + cos squared) (sin + cos)(1 + sin.cos)
9y cubed plus 2y squared
The answer is 100.
(x - 1)(x - 1)(x - 1) - (x + 1)(x + 1)(x + 1)
3-cubed plus 2 plus 1 plus 4= 34
(X + 1)3 = X3 + 3X2 + 3X + 1
2 cubed = 2*2*2 =8. 8+8+8= 24
(x - 1)(2x^2-1)
(2x + 1)(4x^2 - 2x + 1)