3a(b+c)+2b(b+c)
0.3333
the answer to factorising (a x a3 + 2ab + b2) would be (a4+2ab+b2)
In its most simplified form: = 12abc + 8bc - 20ab = 4b(3ac + 2c - 5a) = 4b[(c + 5/3)(3a + 2) - 10/3]
Factorising, we obtain, x2 + 10x + 21 = (x + 7)(x + 3). Thus, x2 + 10x + 21 / (x + 3) = x + 7. That's usually easier than dividing it out!
3ac + 2ca = 3ac + 2ac = (3 + 2)(ac) = 5ac
(6ab + 9b)/(2a + 3) = 3b(2a + 3)/(2a + 3) = 3b
3ab + 3ac + 2b2 + 2bc = 3a(b + c) + 2b(b + c) = (3a + 2b)(b + c)
5 + 10ac + 3b
2 is.
3a(b+c)+2b(b+c)
Factorizing 3ab + 3ac gives 3a (b + c).Factorizing is to express a number or expression as a product of factors.When factorizing always look for common factors. To factorize (3ab + 3ac) look for the highest factor between the two terms (3a). 3ab + 3ac = 3a (b + c)
3ac
This has a degree of 2.
6a^b-18ab^2+24ab
6ab(2x2+x-5)
4ab - 2a - 7