3a(b+c)+2b(b+c)
(a+b)(3b+1)
6
12ab+3ab=15ab
It is an algebraic expression because it has no equality sign.
To find the common factor of the terms (6xyz) and (9abx), we first identify the coefficients and the variables. The greatest common factor of the coefficients 6 and 9 is 3. The common variable in both terms is (x). Thus, the factor of (6xyz + 9abx) is (3x), and we can express it as (3x(2yz + 3ab)).
(3a - 2c)(b - d)
To factor the expression 3ab + 3ac + 2b^2 + 2bc, we first look for common factors among the terms. We can factor out a 3a from the first two terms, and a 2 from the last two terms. This gives us 3a(b + c) + 2(b^2 + bc). Next, we notice that we can factor out a b from the second term in the second parenthesis, giving us the final factored form: 3a(b + c) + 2b(b + c).
(a+b)(3b+1)
(3b - 1)(a - b)
6
12ab+3ab=15ab
(3b - 1)(a - b)
Factorizing 3ab + 3ac gives 3a (b + c).Factorizing is to express a number or expression as a product of factors.When factorizing always look for common factors. To factorize (3ab + 3ac) look for the highest factor between the two terms (3a). 3ab + 3ac = 3a (b + c)
3ab - a - 3b2 + b = -3b2 + 3ab + b - a = -3b(b - a) + 1(b - a) = (1 - 3b)(b - a)
It is: 3ab
3ab[35 - 4]
-2ab